标签:mic -- mamicode com struct swap else const while
https://www.luogu.org/problemnew/show/P2486
值的一看https://www.cnblogs.com/Tony-Double-Sky/p/9283262.html
#include<bits/stdc++.h> using namespace std; const int maxn = 100010; vector<int>G[maxn]; int n , q ,cnt; int siz[maxn] , wson[maxn],dep[maxn],fa[maxn],top[maxn],pos[maxn],ori[maxn]; void dfs1(int id , int F) { siz[id]=1; for(int i=0 ; i<G[id].size() ; i++) { int v=G[id][i]; if(v==F) continue; dep[v] = dep[id] + 1; fa[v] = id; dfs1(v,id); siz[id] += siz[v]; if(siz[v] > siz[wson[id]]) wson[id] = v; } } void dfs2(int id , int TP) { top[id] = TP; pos[id] = ++cnt; ori[cnt]=id; if(!wson[id]) return ; dfs2(wson[id],TP); for(int i=0 ; i<G[id].size() ; i++) { int v=G[id][i]; if(v==fa[id] || v==wson[id]) continue; dfs2(v,v); } } int lc[maxn<<2] , rc[maxn<<2],col[maxn]; #define lson (id<<1) #define rson (id<<1) | 1 struct no { int l,r; int sum,c;///区间颜色总数 , 叶子颜色 int lazy;///儿子的颜色 }tree[maxn<<2]; void build(int id , int l , int r) { tree[id].l=l; tree[id].r=r; if(l==r) { tree[id].c=col[ori[l]];//赋值:叶子颜色 lc[id]=rc[id]=col[ori[l]];//赋值:区间左颜色和区间右颜色 tree[id].sum=1;//颜色数为1 return ; } int mid = (l+r)>>1; build(lson , l , mid); build(rson , mid+1 , r); tree[id].sum = tree[lson].sum + tree[rson].sum; if(rc[lson] == lc[rson]) tree[id].sum-=1; lc[id] = lc[lson]; rc[id] = rc[rson]; } void pushdown(int id) { if(tree[id].lazy!=0 && tree[id].l != tree[id].r) { int c=tree[id].lazy; tree[lson].lazy = tree[rson].lazy=c; tree[lson].c = tree[rson].c = c; lc[lson]=lc[rson]=rc[lson]=rc[rson]=c; tree[lson].sum = tree[rson].sum=1; tree[id].lazy=0; } } void update(int id ,int c , int l , int r) { pushdown(id); if(tree[id].l == l && tree[id].r==r) { tree[id].c=c; tree[id].lazy=c; tree[id].sum=1; lc[id]=rc[id]=c; return ; } int mid=tree[id].l + tree[id].r >> 1; if(mid < l) update(rson,c,l,r); else if(mid>=r) update(lson,c,l,r); else { update(lson,c,l,mid); update(rson,c,mid+1,r); } tree[id].sum=tree[lson].sum+tree[rson].sum; if(rc[lson]==lc[rson]) tree[id].sum-=1; lc[id]=lc[lson]; rc[id]=rc[rson]; } int query(int id , int l , int r) { pushdown(id); if(tree[id].l == l && tree[id].r==r) { return tree[id].sum; } int mid=(tree[id].l + tree[id].r) >>1; if(mid < l) return query(rson,l,r); else if(mid >=r) return query(lson,l,r); else { int ret = query(lson,l,mid) + query(rson,mid+1,r); if(rc[lson]==lc[rson]) ret-=1; return ret; } } int Qc(int id , int l ,int r) { pushdown(id); if(tree[id].l==l && tree[id].r==r) { return tree[id].c; } int mid=tree[id].l + tree[id].r >>1; if(mid < l) return Qc(rson,l,r); else return Qc(lson,l,r); } void uprange(int x , int y , int c) { while(top[x]!=top[y]) { if(dep[top[x]] < dep[top[y]]) swap(x,y); update(1,c,pos[top[x]],pos[x]); x=fa[top[x]]; } if(dep[x] > dep[y]) swap(x,y); update(1,c,pos[x],pos[y]); } int Qsum(int x , int y) { int ans=0,Cson,Cfa; while(top[x] != top[y]) { if(dep[top[x]] < dep[top[y]]) swap(x,y); ans+=query(1,pos[top[x]],pos[x]); Cson=Qc(1,pos[top[x]],pos[top[x]]); Cfa=Qc(1,pos[fa[top[x]]] , pos[fa[top[x]]]); if(Cson==Cfa) ans-=1; x=fa[top[x]]; } if(dep[x] > dep[y]) swap(x,y); ans+=query(1,pos[x] , pos[y]); return ans; } int main() { scanf("%d%d",&n,&q); for(int i=1 ; i<=n ; i++) scanf("%d",&col[i]); int u,v; for(int i=1 ; i<n ; i++) { scanf("%d%d",&u,&v); G[u].push_back(v); G[v].push_back(u); } dfs1(1,-1); dfs2(1,1); build(1,1,n); char ask; int c; while(q--) { cin>>ask; scanf("%d%d",&u,&v); if(ask==‘Q‘) { printf("%d\n",Qsum(u,v)); } else { scanf("%d",&c); uprange(u,v,c); } } }
P2486 [SDOI2011]染色(树剖)区间覆盖+区间的连续段
标签:mic -- mamicode com struct swap else const while
原文地址:https://www.cnblogs.com/shuaihui520/p/10747707.html