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leetcode [216]Combination Sum III

时间:2019-04-29 11:01:27      阅读:122      评论:0      收藏:0      [点我收藏+]

标签:positive   note   tmp   numbers   array   add   ret   sed   integer   

Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.

Note:

  • All numbers will be positive integers.
  • The solution set must not contain duplicate combinations.

Example 1:

Input: k = 3, n = 7
Output: [[1,2,4]]

Example 2:

Input: k = 3, n = 9
Output: [[1,2,6], [1,3,5], [2,3,4]]

题目大意:

给定1到9这九个数字,从中选取k个数字,使得这k个数字之和等于n。这k个数字的选择不能重复。

解法:

采用dfs做:

java:

class Solution {
    List<List<Integer>>res;
    private void dfs(int k,int n,int index,List<Integer>tmpSum){
        if(n<0) return;
        if(k==0){
            if(n==0) res.add(new ArrayList<>(tmpSum));
            return;
        }
        for(int i=index;i<10;i++){
            tmpSum.add(i);
            dfs(k-1,n-i,i+1,tmpSum);
            tmpSum.remove(tmpSum.size()-1);
        }
    }

    public List<List<Integer>> combinationSum3(int k, int n) {
        res=new ArrayList();
        List<Integer>tmpSum=new ArrayList<>();
        dfs(k,n,1,tmpSum);
        return res;
    }
}

  

leetcode [216]Combination Sum III

标签:positive   note   tmp   numbers   array   add   ret   sed   integer   

原文地址:https://www.cnblogs.com/xiaobaituyun/p/10789001.html

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