POJ 2449 Remmarguts' Date ( Dijkstra + A* 求解第K短路 )

标签：算法   dijkstra   

#include <iostream>
#include <cstring>
#include <queue>
#include <fstream>
using namespace std;

#define E 100005
#define V 1005
#define INF 1 << 30

int heads[V], r_heads[V];
int dists[V];
bool visits[V];

int nEdgeNum, nNodeNum, nEdgeCount;
int nEnd, nSrc, k;


struct Edge{

    int to_node;
    int next_edge;
    int edge_weight;

    int r_to_node;
    int r_next_edge;

    Edge(){}
    Edge( int from, int to, int weight ){
        to_node     = to;
        r_to_node   = from;
        edge_weight = weight;
     }

}edges[E];


struct Node{

    int v;
    int src_to_v_dist;

    Node(){
        this->v             = 0;
        this->src_to_v_dist = 0;
    }
    Node( int v, int d ){
        this->v             = v;
        this->src_to_v_dist = d;
    }
    bool operator < ( const Node& other ) const{
        return src_to_v_dist + dists[v] > dists[other.v] + other.src_to_v_dist;
    }

};


void addEdge( int from, int to, int dist ){

    edges[nEdgeCount]             = Edge( from, to, dist );
    edges[nEdgeCount].r_next_edge = r_heads[to];
    edges[nEdgeCount].next_edge   = heads[from];
    heads[from]                   = nEdgeCount;
    r_heads[to]                   = nEdgeCount;

    nEdgeCount++;

}


void dijkstra( int src ){

    priority_queue< Node > que;

    for( int i = 1; i <= nNodeNum; ++i )
        dists[i] = INF;

    dists[src] = 0;
    que.push( Node( src, 0 ) );

    while( !que.empty() ){

        Node cur = que.top();
        que.pop();

        if( visits[cur.v] )
            continue;

        visits[cur.v] = true;

        for( int i = r_heads[cur.v]; ~i; i = edges[i].r_next_edge ){
            if( dists[edges[i].r_to_node] > dists[cur.v] + edges[i].edge_weight ){
                dists[edges[i].r_to_node] = dists[cur.v] + edges[i].edge_weight;
                que.push( Node( edges[i].r_to_node, 0 ) );
            }
        }
    }
}


int AStar( int src ){

    priority_queue< Node > que;

    que.push( Node( src, 0 ) );

    while( !que.empty() ){

        Node cur = que.top();
        que.pop();

        if( cur.v == nEnd ){
            if( k > 1 )
                k--;
            else
                return cur.src_to_v_dist;
        }

        for( int i = heads[cur.v]; ~i; i = edges[i].next_edge )
            que.push( Node( edges[i].to_node, cur.src_to_v_dist + edges[i].edge_weight ) );

    }

    return -1;

}


void init(){
    memset( visits,  false, sizeof( visits ) );
    memset( heads,   -1,    sizeof( heads ) );
    memset( r_heads, -1,    sizeof( r_heads ) );
    nEdgeCount = 0;
}


int main(){

    //fstream fin( "t.txt" );

    while( cin >> nNodeNum >> nEdgeNum ){

        init();

        for( int i = 1; i <= nEdgeNum; ++i ){

            int from, to, dist;

            cin >> from >> to >> dist;

            addEdge( from, to, dist );

        }

        cin >> nSrc >> nEnd >> k;

        dijkstra( nEnd );

        if( dists[nSrc] == INF ){
            cout << "-1\n";
            continue;
        }

        if( nSrc == nEnd )
            k++;

        int ans = AStar( nSrc );

        cout << ans << endl;

    }

    return 0;
}

POJ 2449 Remmarguts' Date ( Dijkstra + A* 求解第K短路 )

标签：算法   dijkstra   

原文地址：http://blog.csdn.net/pandora_madara/article/details/40324725