标签：style precise com panel 价值 mes ota ++ from
In the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of the heroes. The hook is made up of several consecutive metallic sticks which are of the same length.
InputThe input consists of several test cases. The first line of the input is the number of the cases. There are no more than 10 cases.
For each case, the first line contains an integer N, 1<=N<=100,000, which is the number of the sticks of Pudge’s meat hook and the second line contains an integer Q, 0<=Q<=100,000, which is the number of the operations.
Next Q lines, each line contains three integers X, Y, 1<=X<=Y<=N, Z, 1<=Z<=3, which defines an operation: change the sticks numbered from X to Y into the metal kind Z, where Z=1 represents the cupreous kind, Z=2 represents the silver kind and Z=3 represents the golden kind.
OutputFor each case, print a number in a line representing the total value of the hook after the operations. Use the format in the example.
Sample Input
1 10 2 1 5 2 5 9 3
Sample Output
Case 1: The total value of the hook is 24.
解题思路：题目大意：在DOTA里有一个英雄帕琪（不玩，不知道叫啥，还是屠夫来着），他有一个肉钩，巨长，然后默认都是黄铜做的，
每一节的价值都为1。然后他要改变钩子连续链节，换成别的材质。然后题目开始输入样例的个数，然后是钩子的链节数，接下来是操作的次数。
后面就是更改了，1是黄铜，2是白银，3是金，价值也是这个数。
这是区间值的修改，所以不同于之前的区间累加，lazy值是不用累加的；
代码如下：
1 #include<iostream> 2 #include<stdio.h> 3 using namespace std; 4 5 int T; 6 int N; 7 int M; 8 const int MAXN = 1000005; 9 int a[MAXN]; 10 int tree[MAXN*4]; 11 int lazy[MAXN*4]; 12 int x , y , k ; 13 int num = 0; 14 void push_down(int l ,int r ,int rt) 15 { 16 int m = (l+r)/2; 17 18 if(lazy[rt]) 19 { 20 tree[rt*2] = lazy[rt]*(m-l+1); 21 tree[rt*2+1] = lazy[rt]*(r-m); 22 lazy[rt*2] = lazy[rt]; 23 lazy[rt*2+1] = lazy[rt]; 24 lazy[rt] = 0; 25 } 26 } 27 void bulid_tree(int l ,int r ,int rt) 28 { 29 lazy[rt] = 0; 30 if(l==r) 31 { 32 tree[rt] = a[l]; 33 return ; 34 } 35 int m = (l+r)/2; 36 bulid_tree(l,m,rt*2); 37 bulid_tree(m+1,r,rt*2+1); 38 tree[rt] = tree[rt*2]+tree[rt*2+1]; 39 } 40 41 void Update(int x ,int y ,int value, int l ,int r ,int rt) 42 { 43 if(x<=l&&r<=y) 44 { 45 tree[rt] = value*(r-l+1); 46 lazy[rt] = value; 47 return ; 48 } 49 push_down(l,r,rt); 50 int m = (l+r)/2; 51 52 if(x<=m) 53 { 54 Update(x,y,value,l,m,rt*2); 55 } 56 57 if(y>m) 58 { 59 Update(x,y,value,m+1,r,rt*2+1); 60 } 61 tree[rt] = tree[rt*2] +tree[rt*2+1]; 62 } 63 int main() 64 { 65 scanf("%d",&T); 66 while(T--) 67 { 68 num++; 69 scanf("%d",&N); 70 for(int i = 1 ; i <= N ;i++) 71 { 72 a[i] = 1; //首先全部是铜，值为1； 73 } 74 bulid_tree(1,N,1); 75 scanf("%d",&M); 76 while(M--) 77 { 78 scanf("%d%d%d",&x,&y,&k); 79 Update(x,y,k,1,N,1); 80 } 81 printf("Case %d: The total value of the hook is %d.\n",num,tree[1]); //根实际上就是总和； 82 } 83 return 0; 84 }
HDU - 1698 Just a Hook(线段树区间整体修改值，查询区间和）
标签：style precise com panel 价值 mes ota ++ from
原文地址：https://www.cnblogs.com/yewanting/p/10801342.html
