码迷,mamicode.com
首页 > 其他好文 > 详细

poj3345

时间:2019-05-02 18:40:43      阅读:141      评论:0      收藏:0      [点我收藏+]

标签:ace   nbsp   return   ble   txt   struct   cas   pair   stack   

注意》=m就行。

#include <iostream>
#include <cstdio>
#include <cmath>
#include <algorithm>
#include <vector>
#include <iomanip>
#include <cstring>
#include <map>
#include <queue>
#include <set>
#include <cassert>
#include <stack>
#include <bitset>
#include <unordered_set>
#define mkp make_pair
//#define err cout<<"here"<<endl
using namespace std;
const double EPS=1e-12;
typedef long long lon;
typedef unsigned long long ull;
typedef set<int>::iterator IT;
const lon SZ=220,SSZ=120,APB=52,mod=97,one=1;
const lon INF=0x7FFFFFFF;
int n,m,arr[SZ],in[SZ],dp[SZ][SZ];
struct nd{
    int to,wt;
    nd(int a=0,int b=0):to(a),wt(b){}
};
char ch[SZ];
map<string,int> st;
int cnt=0,siz[SZ];
vector<int> mp[SZ];
    
bool read()
{
    for(;cin.peek()== ;cin.get());
    //cout<<(cin.peek()==‘\n‘)<<endl;
    if(cin.peek()==\n)
    {
        cin.get();
        return 0;
    }
    int sz=0;
    for(;cin.peek()!= &&cin.peek()!=\n;)ch[sz++]=cin.get();
    ch[sz]=0;
    //cout<<ch<<endl;
    return 1;
}

void build(int x)
{
    for(;read();)
    {
        string str(ch);
        if(st.find(str)==st.end())st[str]=++cnt;
        int id=st[str];
        mp[x].push_back(id);
        ++in[id];
    }
}

void init()
{
    cin>>n>>m;
    for(int i=0;i<=n;++i)mp[i].clear();
    st.clear(),cnt=0;
    memset(in,0,sizeof(in));
    for(int i=1;i<=n;++i)
    {
        //cout<<"i: "<<i<<endl;
        for(;cin.peek()== ||cin.peek()==\n;cin.get());
        read();
        string str(ch);
        if(st.find(str)==st.end())st[str]=++cnt;
        int id=st[str];
        cin>>arr[id];
        build(id);
    }
    for(int i=1;i<=cnt;++i)
    {
        if(in[i]==0)mp[0].push_back(i);
    }
    arr[0]=INF;
    memset(dp,0x3f,sizeof(dp));
}

void dfs(int x)
{
    siz[x]=1;
    dp[x][0]=0;
    for(int k=0;k<mp[x].size();++k)
    {
        int to=mp[x][k];
        dfs(to);
        siz[x]+=siz[to];
        for(int i=siz[x]-1;i>=0;--i)
        {
            for(int j=0;j<=i;++j)
            {
                dp[x][i]=min(dp[x][i],dp[x][i-j]+dp[to][j]);
            }
            //cout<<x<<" "<<i<<" "<<dp[x][i]<<endl;
        }
    }
    dp[x][siz[x]]=arr[x];
}

void work()
{
    dfs(0);
    int res=INF;
    for(int i=m;i<SZ;++i)res=min(res,dp[0][i]);
    cout<<res<<endl;
}

void release()
{
    //memset(dp,0,sizeof(dp));
    //memset(num,0,sizeof(num));
    
}

int main()
{
    std::ios::sync_with_stdio(0);
    //freopen("d:\\1.txt","r",stdin);
    int casenum;
    //memset(dst,0x5a,sizeof(dst));
    //cout<<dst[0][0]<<endl;
    //cin>>casenum;
    //cout<<casenum<<endl;
    //for(int time=1;time<=casenum;++time)
    for(int time=1;;++time)
    {
        for(;cin.peek()== ||cin.peek()==\n;cin.get());
        if(cin.peek()==#)break;
        init();
        work();
        release();
    }
    return 0;
}

 

poj3345

标签:ace   nbsp   return   ble   txt   struct   cas   pair   stack   

原文地址:https://www.cnblogs.com/gaudar/p/10802837.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!