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LintCode 14---二分查找

时间:2019-05-06 01:19:14      阅读:133      评论:0      收藏:0      [点我收藏+]

标签:from   integer   array   nbsp   osi   ret   int   pos   find   

public class Solution {
    /**
     * @param nums: The integer array.
     * @param target: Target to find.
     * @return: The first position of target. Position starts from 0.
     */
    public int binarySearch(int[] nums, int target) {
         int left = 0,right = nums.length-1;
            int mid = (left + right) / 2;
            while (left < right) {
                if (nums[mid] < target) left = mid + 1;
                if (nums[mid] >= target) right = mid;
                mid = (left + right) / 2;
            }
            return nums[mid] == target ? mid : -1;
    }
}

 

LintCode 14---二分查找

标签:from   integer   array   nbsp   osi   ret   int   pos   find   

原文地址:https://www.cnblogs.com/cnmoti/p/10817148.html

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