Given an array of integers, every element appears three times except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class Solution { public: int singleNumber(int A[], int n) { sort(A,A+n); for(int i=0;i<n;i=i+3) { if(A[i]!=A[i+2]) return A[i]; } } };
LeetCode--Single Number II,布布扣,bubuko.com
原文地址:http://blog.csdn.net/greenapple_shan/article/details/25834047