标签:[1] ons || long 字符串匹配 while c++ ext type
来一道模板题,直接上代码。
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 1e6 + 5;
int n, m;
char s1[N], s2[N];
int nxt[N] ;
void Get_next(char *s) {
int j, L = strlen(s + 1);
nxt[1] = j = 0;
for(int i = 2; i <= L; i++) {
while(j && s[i] != s[j + 1]) j = nxt[j] ;
if(s[i] == s[j + 1]) j++;
nxt[i] = j;
}
}
int main() {
scanf("%s%s", s1 + 1, s2 + 1);
Get_next(s2) ;
int L1 = strlen(s1 + 1), L2 = strlen(s2 + 1) ;
for(int i = 1, j = 0; i <= L1; i++) {
while(j > 0 && (j == L2 || s1[i] != s2[j + 1])) j = nxt[j] ;
if(s1[i] == s2[j + 1]) j++;
if(j == L2) cout << i - L2 + 1 << '\n' ;
}
for(int i = 1; i <= L2; i++) cout << nxt[i] << ' ' ;
return 0;
}
标签:[1] ons || long 字符串匹配 while c++ ext type
原文地址:https://www.cnblogs.com/heyuhhh/p/10877706.html