Series Determination
18 32 50
#include<iostream>
using
namespace
std;
int
main()
{
int
n;
int
a,b,c;
while
(cin>>a>>b>>c)
{
cout<<1*a-3*b+3*c<<
"
"
;
cout<<3*a-8*b+6*c<<
"
"
;
cout<<6*a-15*b+10*c;
cout<<endl;
}
}
此题读懂题意,即使根据f(0),f(1),f(2)值求得f(3)f(4)f(5)
可通过待定系数法得到每一个结果表达式,进行运算即可
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原文地址:http://blog.csdn.net/u013240812/article/details/25830831