剑指offer-重建二叉树

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* build(vector<int> v1,int s1,int e1,vector<int> v2,int s2,int e2)
    {
        if(s1 >= e1 || s2 >= e2)
            return NULL;
        int k;
        for(k = s2;k < e2;k++)
        {
            if(v2[k] == v1[s1])
            {
                break;
            }
        }
        TreeNode* root = new TreeNode(v1[s1]);
        root->left = build(v1,s1+1,s1 + k - s2 + 1,v2,s2,k+1);
        root->right = build(v1,s1 + k - s2 + 1,e1,v2,k+1,e2);
        return root;
    }
    TreeNode* reConstructBinaryTree(vector<int> pre,vector<int> vin) {
        return build(pre,0,pre.size(),vin,0,vin.size());
    }
};