标签:bool isp clu push printf pen 题解 space else
题目描述:
题解:
计算几何,叉积判断方向。
然后整体二分即可。
#include<cmath> #include<vector> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int N = 5050; const double eps = 1e-8; struct Point { double x,y; Point(){} Point(double x,double y):x(x),y(y){} Point operator - (const Point&a)const{return Point(x-a.x,y-a.y);} double operator ^ (const Point&a)const{return x*a.y-y*a.x;} }; typedef Point Vector; struct Line { Point p; Vector v; Line(){} Line(Point p,Vector v):p(p),v(v){} }; Line s[N]; int n,m; double x_1,y_1,x_2,y_2; int dcmp(double x) { if(fabs(x)<=eps)return 0; return x>0?1:-1; } bool Onleft(Line l,Point p) { return dcmp(l.v^(p-l.p))>0; } void dv(int l,int r,vector<Point>&ve) { if(l==r) { printf("%d: %d\n",l,ve.size()); return ; } int mid = ((l+r)>>1)+1; vector<Point>vl,vr; for(int i=0,lim=(int)ve.size();i<lim;i++) if(Onleft(s[mid],ve[i]))vl.push_back(ve[i]); else vr.push_back(ve[i]); dv(l,mid-1,vl); dv(mid,r,vr); } int main() { while(scanf("%d%d%lf%lf%lf%lf",&n,&m,&x_1,&y_1,&x_2,&y_2)==6) { double x,y; for(int i=1;i<=n;i++) { scanf("%lf%lf",&x,&y); s[i] = Line(Point(y,y_2),Point(x,y_1)-Point(y,y_2)); } vector<Point>v0; for(int i=1;i<=m;i++) { scanf("%lf%lf",&x,&y); v0.push_back(Point(x,y)); } dv(0,n,v0); puts(""); } return 0; }
标签:bool isp clu push printf pen 题解 space else
原文地址:https://www.cnblogs.com/LiGuanlin1124/p/10981257.html