标签：self ret else solution lse leetcode code tco turn
mycode time limited
例如 x=0.00001 n=2147483647
参考：
class Solution(object): def myPow(self, x, n): """ :type x: float :type n: int :rtype: float """ if n == 0 : return 1 if n < 0 : return 1.0/self.myPow(x,-n) if n%2 == 1 : print(x,n) return x*self.myPow(x*x,n//2) else: print(x,n) return self.myPow(x*x,n//2)
标签：self ret else solution lse leetcode code tco turn
原文地址：https://www.cnblogs.com/rosyYY/p/10981997.html
