标签:des style blog color io os ar for sp
Given a binary tree, return the postorder traversal of its nodes‘ values.
For example:
Given binary tree {1,#,2,3}
,
1 2 / 3
return [3,2,1]
.
Note: Recursive solution is trivial, could you do it iteratively?
Solution 1: 非递归
Solution 2: 递归
1 /** 2 * Definition for binary tree 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public List<Integer> postorderTraversal(TreeNode root) { 12 List<Integer> result=new ArrayList<Integer>(); 13 myPostorderTraversal(root,result); 14 return result; 15 } 16 17 private void myPostorderTraversal(TreeNode root, List<Integer> result) { 18 // TODO Auto-generated method stub 19 if(root!=null){ 20 myPostorderTraversal(root.left, result); 21 myPostorderTraversal(root.right, result); 22 result.add(root.val); 23 } 24 } 25 }
[Leetcode] Binary Tree Postorder Traversal
标签:des style blog color io os ar for sp
原文地址:http://www.cnblogs.com/Phoebe815/p/4042933.html