标签:pre inpu oat def turn 操作 %s obj else
part1
#include <stdio.h> const int N=5; typedef struct student { long no; char name[20]; int score; }STU; void input(STU s[], int n); int findMinlist(STU s[], STU t[], int n); void output(STU s[], int n); int main() { STU stu[N], minlist[N]; int count; printf("录入%d个学生信息\n", N); input(stu, N); printf("\n统计最低分人数和学生信息...\n"); count = findMinlist(stu, minlist, N); printf("\n一共有%d个最低分,信息如下:\n", count); output(minlist, count); return 0; } void input(STU s[], int n) { int i; for(i=0; i<n; i++) scanf("%ld %s %d", &s[i].no, s[i].name, &s[i].score); } void output(STU s[], int n) { int i; for(i=0; i<n; i++) printf("%ld %s %d\n", s[i].no, s[i].name, s[i].score); } int findMinlist(STU s[], STU t[], int n) { int i,j,k=0,count=0; STU temp; for(i=0;i<n;i++){ for(j=i;j<n;j++){ if(s[j].score<s[i].score){ temp=s[i]; s[i]=s[j]; s[j]=temp; } } } t[k]=s[count]; while(t[k].score==s[++count].score) t[++k]=s[count]; return count;
}
part2
#include <stdio.h> #include <string.h> const int N = 10; typedef struct student { long int id; char name[20]; float objective; float subjective; float sum; char level[10]; }STU; void input(STU s[], int n); void output(STU s[], int n); void process(STU s[], int n); int main() { STU stu[N]; printf("录入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分(<=60)\n", N); input(stu, N); printf("\n对考生信息进行处理: 计算总分,确定等级\n"); process(stu, N); printf("\n打印考生完整信息:准考证号,姓名,客观题得分,操作题得分,总分,等级\n"); output(stu, N); return 0; } void input(STU s[], int n) { int i; for(i=0;i<n;i++) scanf("%d %s %f %f",&s[i].id,&s[i].name,&s[i].objective,&s[i].subjective); } void output(STU s[], int n) { int i; for(i=0;i<n;i++){ printf("%5d %10s %5.1f %5.1f %5.1f %10s\n",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level); } } void process(STU s[], int n) { int i,j,k,m=0; STU temp; for(i=0;i<n;i++) s[i].sum=s[i].objective+s[i].subjective; for(j=0;j<n;j++){ for(k=j;k<n;k++){ if(s[j].sum<s[k].sum){ temp=s[j]; s[j]=s[k]; s[k]=temp; } } } while(m<=n){ if(m<=n*0.1-1) strcpy(s[m].level,"优秀"); else if(m>n*0.1-1&&m<=n*0.5-1) strcpy(s[m].level,"合格"); else strcpy(s[m].level,"不合格"); m++; }; }
标签:pre inpu oat def turn 操作 %s obj else
原文地址:https://www.cnblogs.com/74520qslm/p/11001090.html