推导式

li = [ 6*i for i in range(10)]
print(li)
-----------------------------------------
[0, 6, 12, 18, 24, 30, 36, 42, 48, 54]

-----------------------------------------
str = ["输出%s" %i for i in range(10)]
print(str)
-----------------------------------------
[‘输出9‘, ‘输出5‘, ‘输出1‘, ‘输出0‘, ‘输出4‘, ‘输出8‘, ‘输出2‘, ‘输出6‘, ‘输出7‘, ‘输出3‘]

----------------------------------------
#添加if条件

multiples = [i for i in range(30) if i % 3 is 0]
print(multiples)
# Output: [0, 3, 6, 9, 12, 15, 18, 21, 24, 27]
------------------------------------------------------

#找到嵌套列表中名字含有两个‘e’的所有名字
names = [[‘Tom‘, ‘Billy‘, ‘Jefferson‘, ‘Andrew‘, ‘Wesley‘, ‘Steven‘, ‘Joe‘],
         [‘Alice‘, ‘Jill‘, ‘Ana‘, ‘Wendy‘, ‘Jennifer‘, ‘Sherry‘, ‘Eva‘]]

print([name for lst in names for name in lst if name.count(‘e‘) >= 2])  # 注意遍历顺序，这是实现的关键
 

li = ( 2*i for i in range(10))
print(li)
print(next(li)) # #next本质就是调用__next__
print(li.__next__())
print(next(li))
----------------------------------------
2
4
6
----------------------------------------

for i in li:
    print(i)