1025 PAT Ranking (25 分)
标签：for rap job generate amp problem red enter class
Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. Now it is your job to write a program to correctly merge all the ranklists and generate the final rank.
Each input file contains one test case. For each case, the first line contains a positive number N (≤), the number of test locations. Then N ranklists follow, each starts with a line containing a positive integer K (≤), the number of testees, and then Klines containing the registration number (a 13-digit number) and the total score of each testee. All the numbers in a line are separated by a space.
For each test case, first print in one line the total number of testees. Then print the final ranklist in the following format:
registration_number final_rank location_number local_rank
The locations are numbered from 1 to N. The output must be sorted in nondecreasing order of the final ranks. The testees with the same score must have the same rank, and the output must be sorted in nondecreasing order of their registration numbers.
2
5
1234567890001 95
1234567890005 100
1234567890003 95
1234567890002 77
1234567890004 85
4
1234567890013 65
1234567890011 25
1234567890014 100
1234567890012 85
9 1234567890005 1 1 1 1234567890014 1 2 1 1234567890001 3 1 2 1234567890003 3 1 2 1234567890004 5 1 4 1234567890012 5 2 2 1234567890002 7 1 5 1234567890013 8 2 3 1234567890011 9 2 4
排序加模拟
1 #include <bits/stdc++.h> 2 #define N 305 3 using namespace std; 4 int n, m,pos = 0; 5 struct Node{ 6 string num; 7 int score; 8 int final_rank; 9 int cc; 10 int local_rank; 11 }node[N],final[N*100]; 12 bool cmp(Node a, Node b){ 13 if(a.score == b.score){ 14 return a.num < b.num; 15 } 16 return a.score > b.score; 17 } 18 19 int main(){ 20 cin >> n; 21 for(int i = 1; i<=n; i++){ 22 cin >> m; 23 for(int j = 0; j < m; j++){ 24 cin >> node[j].num >> node[j].score; 25 } 26 sort(node,node+m,cmp); 27 for(int j = 0; j < m; j++){ 28 node[j].cc = i; 29 if(j == 0) 30 node[j].local_rank = j+1; 31 else{ 32 if(node[j].score == node[j-1].score) 33 node[j].local_rank = node[j-1].local_rank; 34 else 35 node[j].local_rank = j+1; 36 } 37 final[pos++] = node[j]; 38 } 39 } 40 sort(final,final+pos,cmp); 41 cout << pos << endl; 42 for(int i = 0; i < pos; i++){ 43 if(i==0){ 44 final[i].final_rank = i+1; 45 cout <<final[i].num<<" "<<final[i].final_rank<<" "<<final[i].cc<<" "<<final[i].local_rank<<endl; 46 }else{ 47 if(final[i].score == final[i-1].score) 48 final[i].final_rank = final[i-1].final_rank; 49 else 50 final[i].final_rank = i+1; 51 cout <<final[i].num<<" "<<final[i].final_rank<<" "<<final[i].cc<<" "<<final[i].local_rank<<endl; 52 } 53 } 54 return 0; 55 }
标签：for rap job generate amp problem red enter class
原文地址：https://www.cnblogs.com/zllwxm123/p/11049882.html
