标签:line ati queue || 技术 max sed ack pre
题目链接:https://vjudge.net/problem/UVA-221
题目翻译摘自《算法禁赛入门经典》
有n(n ≤ 100)个建筑物。
输入每个建筑物左下角坐标(x,y)、宽度(即 x 方向的长度)、深度 (即 y 方向的长度)和高度(以上数据均为实数),输出正视图中能看到的所有建筑物,按 照左下角 x 坐标从小到大进行排序。左下角 x 坐标相同时,按 y 坐标从小到大排序。
输入保证不同的 x 坐标不会很接近(即任意两个 x 坐标要么完全相同,要么差别足够大, 不会引起精度问题)。
1 #include <bits/stdc++.h> 2 using namespace std; 3 4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); 5 #define Rep(i,n) for (int i = 0; i < (n); ++i) 6 #define For(i,s,t) for (int i = (s); i <= (t); ++i) 7 #define rFor(i,t,s) for (int i = (t); i >= (s); --i) 8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i) 9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i) 10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i) 11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i) 12 13 #define pr(x) cout << #x << " = " << x << " " 14 #define prln(x) cout << #x << " = " << x << endl 15 16 #define LOWBIT(x) ((x)&(-x)) 17 18 #define ALL(x) x.begin(),x.end() 19 #define INS(x) inserter(x,x.begin()) 20 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end()) 21 22 #define ms0(a) memset(a,0,sizeof(a)) 23 #define msI(a) memset(a,inf,sizeof(a)) 24 #define msM(a) memset(a,-1,sizeof(a)) 25 26 #define MP make_pair 27 #define PB push_back 28 #define ft first 29 #define sd second 30 31 template<typename T1, typename T2> 32 istream &operator>>(istream &in, pair<T1, T2> &p) { 33 in >> p.first >> p.second; 34 return in; 35 } 36 37 template<typename T> 38 istream &operator>>(istream &in, vector<T> &v) { 39 for (auto &x: v) 40 in >> x; 41 return in; 42 } 43 44 template<typename T1, typename T2> 45 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) { 46 out << "[" << p.first << ", " << p.second << "]" << "\n"; 47 return out; 48 } 49 50 inline int gc(){ 51 static const int BUF = 1e7; 52 static char buf[BUF], *bg = buf + BUF, *ed = bg; 53 54 if(bg == ed) fread(bg = buf, 1, BUF, stdin); 55 return *bg++; 56 } 57 58 inline int ri(){ 59 int x = 0, f = 1, c = gc(); 60 for(; c<48||c>57; f = c==‘-‘?-1:f, c=gc()); 61 for(; c>47&&c<58; x = x*10 + c - 48, c=gc()); 62 return x*f; 63 } 64 65 template<class T> 66 inline string toString(T x) { 67 ostringstream sout; 68 sout << x; 69 return sout.str(); 70 } 71 72 inline int toInt(string s) { 73 int v; 74 istringstream sin(s); 75 sin >> v; 76 return v; 77 } 78 79 //min <= aim <= max 80 template<typename T> 81 inline bool BETWEEN(const T aim, const T min, const T max) { 82 return min <= aim && aim <= max; 83 } 84 85 typedef long long LL; 86 typedef unsigned long long uLL; 87 typedef pair< double, double > PDD; 88 typedef pair< int, int > PII; 89 typedef pair< int, PII > PIPII; 90 typedef pair< string, int > PSI; 91 typedef pair< int, PSI > PIPSI; 92 typedef set< int > SI; 93 typedef set< PII > SPII; 94 typedef vector< int > VI; 95 typedef vector< double > VD; 96 typedef vector< VI > VVI; 97 typedef vector< SI > VSI; 98 typedef vector< PII > VPII; 99 typedef map< int, int > MII; 100 typedef map< int, string > MIS; 101 typedef map< int, PII > MIPII; 102 typedef map< PII, int > MPIII; 103 typedef map< string, int > MSI; 104 typedef map< string, string > MSS; 105 typedef map< PII, string > MPIIS; 106 typedef map< PII, PII > MPIIPII; 107 typedef multimap< int, int > MMII; 108 typedef multimap< string, int > MMSI; 109 //typedef unordered_map< int, int > uMII; 110 typedef pair< LL, LL > PLL; 111 typedef vector< LL > VL; 112 typedef vector< VL > VVL; 113 typedef priority_queue< int > PQIMax; 114 typedef priority_queue< int, VI, greater< int > > PQIMin; 115 const double EPS = 1e-8; 116 const LL inf = 0x7fffffff; 117 const LL infLL = 0x7fffffffffffffffLL; 118 const LL mod = 1e9 + 7; 119 const int maxN = 1e4 + 7; 120 const LL ONE = 1; 121 const LL evenBits = 0xaaaaaaaaaaaaaaaa; 122 const LL oddBits = 0x5555555555555555; 123 124 struct Building{ 125 int id; 126 double Y, L, R, h; 127 128 Building() {} 129 Building(int x) : id(x) {} 130 131 bool operator< (const Building &x) const { 132 if(L == x.L) return Y < x.Y; 133 return L < x.L; 134 } 135 }; 136 137 istream& operator >> (istream& in, Building& x){ 138 in >> x.L >> x.Y >> x.R >> x.h >> x.h; 139 x.R += x.L; 140 return in; 141 } 142 143 int N, T; 144 vector< Building > b; 145 VI ans; 146 VD x; 147 148 int main(){ 149 //freopen("MyOutput.txt","w",stdout); 150 //freopen("input.txt","r",stdin); 151 //INIT(); 152 while(cin >> N) { 153 if(!N) break; 154 ans.clear(); 155 b.clear(); 156 x.clear(); 157 158 Rep(i, N) { 159 Building t(i + 1); 160 cin >> t; 161 b.PB(t); 162 x.PB(t.L); 163 x.PB(t.R); 164 } 165 sort(ALL(b)); 166 sort(ALL(x)); 167 UNIQUE(x); 168 169 Rep(i, b.size()) { 170 For(j, lower_bound(ALL(x), b[i].L) - x.begin(), x.size() - 2) { 171 if(x[j] >= b[i].R) break; 172 double m = (x[j] + x[j + 1]) / 2; // 取中点为代表点 173 174 bool flag = true; 175 Rep(k, b.size()) { 176 if(b[k].h >= b[i].h && b[k].Y < b[i].Y && BETWEEN(m, b[k].L, b[k].R)) { 177 flag = false; 178 break; 179 } 180 } 181 182 if(flag) { 183 ans.PB(b[i].id); 184 break; 185 } 186 } 187 } 188 189 if(T) printf("\n"); 190 printf("For map #%d, the visible buildings are numbered as follows:\n", ++T); 191 Rep(i, ans.size()) printf("%d%c", ans[i], " \n"[i == ans.size() - 1]); 192 } 193 return 0; 194 }
标签:line ati queue || 技术 max sed ack pre
原文地址:https://www.cnblogs.com/zaq19970105/p/11066988.html