实战一道2级综合编程模拟题

标签：想法   初学   let   随机密码   ice   man   数据处理   for   def   

请编写程序，生成随机密码。具体要求如下：????????????????????????????????????????????????????????????????????????????????????????????????

（1）使用 random 库，采用 0x1010 作为随机数种子。????????????????????????????????????????????????????????????????????????????????????????????????

（2）密码 abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890!@#$%^&* 中的字符组成。????????????????????????????????????????????????????????????????????????????????????????????????

（3）每个密码长度固定为 10 个字符。????????????????????????????????????????????????????????????????????????????????????????????????

（4）程序运行每次产生 10 个密码，每个密码一行。????????????????????????????????????????????????????????????????????????????????????????????????

（5）每次产生的 10 个密码首字符不能一样。????????????????????????????????????????????????????????????????????????????????????????????????

（6）程序运行后产生的密码保存在“随机密码.txt”文件中。????????????????????????????????????????????????????????????????????????????????????????????????

 ????????????????????????????????????????????????????????????????????????????????????????????????

不写入文件，直接 print 10 个密码即可自动评阅

解析：

通读题目要求，req5是个难点，如何保证产生的10个密码首字符不同？
一个自然的想法是记录并比较
进而对于req4，就不能用for循环固定循环次数，需要用while循环
while循环退出循环的依据是什么？取决于如何记录密码，比如把每次生成的密码记录到一个列表，用len(ls)<10做退出循环的条件
每次生成的密码设为cipher,考虑以及几点
1.如何生成2.如何满足req5.3如何输出
1.如何生成，可以考虑用s[random.randint(0,len(s)-1)]或random.choice(s), s 是字符集
2.如何满足req5,可以记录每个cipher的首字符，并记录在字符串execlude,只有满足的才添加到ls中
3. 输出，每个密码一行，cipher+ ‘\n‘就可以了

具体代码如下：

import random

fo = open(‘D:/bak/skydrive/automation/2级/execise/随机密码.txt‘,‘w‘)
random.seed(0x1010)
s = ‘abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890!@#$%^&*‘
cipher = ‘‘ # store a cipher,store it into ls and then clear it
ls = [] # store all 10 cipher, len(ls) to count the num of cipher
execlude = ‘‘ # store the first char of a cipher,make sure the cipher meet req#5
while len(ls) < 10: # generate 10 cipher, not use for loop as due to req#5, the running time is not predictable
    cipher = ‘‘ # reset cipher each round
    for i in range(10): # 10个字符
        #cipher += random.choice(s) # pickup a random char from s by random.choice and then connect cyper by +
        cipher += s[random.randint(0,len(s)-1)]        
    cipher = cipher + ‘\n‘
    if cipher[0] in execlude:
        continue
    else:
        ls.append(cipher)
        execlude += cipher[0]
        #fo.writelines(cipher) # if write line by line,the performance is somewhat poor,let write the ls to file directly
#print(c)
print(‘‘.join(ls))
##for line in ls:
##    fo.write(line)
fo.write(‘‘.join(ls))
#print(execlude)
fo.close()

    

执行结果：

So2WpkoC7i
armJ86eUG9
B*GcqsYC^B
wQ3bcfcAJy
Xdyg8pQTIS
YO!1YH1AP3
cuhZUk@s5&
D@4d9$TBfp
TBm#WfYNHr
Ue75y$E9Cv

由此，可见2级综合编程题，需要在较短时间内，能解读问题，综合应用各种基本编程技能，完成题目要求，对初学者还是有一定难度的。

需要仔细审题，吃透题意，提高基本数据处理的熟练度，才能从容过关。

实战一道2级综合编程模拟题

标签：想法   初学   let   随机密码   ice   man   数据处理   for   def   

原文地址：https://www.cnblogs.com/jamesxu/p/11079893.html