标签:style null treenode bottom empty stat return span linked
给定一个二叉树,在树的最后一行找到最左边的值。
示例 1:
输入: 2 / 1 3 输出: 1
1 import java.util.LinkedList; 2 import java.util.Queue; 3 4 public class FindBottomLeftValue { 5 static class TreeNode { 6 int val; 7 TreeNode left; 8 TreeNode right; 9 TreeNode(int x) { 10 val = x; 11 } 12 } 13 public int findBottomLeftValue(TreeNode root) { 14 Queue<TreeNode> queue = new LinkedList<>(); 15 TreeNode temp = root; 16 queue.add(root); 17 while(!queue.isEmpty()) { 18 temp = queue.remove(); 19 //先将右子节点添加,从右往左,则可以最后访问最左侧节点 20 if(temp.right != null) { 21 queue.add(temp.right); 22 } 23 if(temp.left != null) { 24 queue.add(temp.left); 25 } 26 } 27 return temp.val; 28 } 29 }
标签:style null treenode bottom empty stat return span linked
原文地址:https://www.cnblogs.com/xiyangchen/p/11108396.html