标签:his import NPU 需要 取值 结果 near amp util
线性探针法哈希表
2019-07-03 11:40:23
import java.io.ObjectInputStream; import java.util.ArrayList; /** * @ClassName LinearProbeHashST * @Author wangyudi * @Date 2019/7/3 10:53 * @Version 1.0 * @Description 用线性试探法实现哈希表 */ public class LinearProbeHashST<Key, Value> { private int m; //数组大小 private int n;//键值对数量 private Key[] keys;//键数组 private Value[] values;//值数组 private ArrayList<Key> arr;//用于迭代的集合 /** * 构造函数 * 初始化数组对 */ public LinearProbeHashST() { this(16); } public LinearProbeHashST(int m) { this.m = m; this.n = 0; this.keys = (Key[]) new Object[m]; this.values = (Value[]) new Object[m]; } /** * 调整数组的大小(对于线性探针哈希表而言,该数组大小调整时必须的) * 需要新建一个哈希表,将源哈希表的数据PUT到新哈希表中,然后把新建符号表的成员给原表 * @param size */ private void resize(int size) { LinearProbeHashST<Key, Value> linearProbeHashST = new LinearProbeHashST<>(size); for (int i = 0; i < m; i++) { if (keys[i] != null) { linearProbeHashST.put(keys[i], values[i]); } } this.m = size; this.values = linearProbeHashST.values; this.keys = linearProbeHashST.keys; } /** * 获取散列值 * @param key * @return */ private int hash(Key key) { return (key.hashCode() & 0x7FFFFFFF) % m; } /** * 向哈希表中添加键值对 * * @param key * @param value */ public void put(Key key, Value value) { if (n > m / 2) resize(m * 2); int i = hash(key); while (keys[i] != null) { if (keys[i].equals(key)) { values[i] = value; return; } i = (i + 1) % m; } keys[i] = key; values[i] = value; n++; } /** * 根据键获取值 * * @param key * @return */ public Value get(Key key) { int i = hash(key); while (keys[i] != null) { if (keys[i].equals(key)) { return values[i]; } i = (i + 1) % m; } return null; } /** * 从哈希表中删除键值对 * * @param key * @return */ public Value delete(Key key) { int i = hash(key); while (keys[i] != null) {//在null前遍历所有键值对 if (keys[i].equals(key)) { //找到该键 Value t = values[i]; keys[i] = null; //删除找到的键 values[i] = null; i = (i + 1) % m; //将删除键后面的键值对重新PUT到哈希表中 while (keys[i] != null) { Key k = keys[i]; Value v = values[i]; keys[i] = null; //必须置为null,不然在键的索引正好是散列值的情况下会出问题 values[i] = null; put(k, v); i = (i + 1) % m; } n--; if (n > 0 && n < m / 8) resize(m / 2); return t; } i = (i + 1) % m; } return null;//未找到该键,则返回null } /** * 返回迭代器 * @return */ public Iterable<Key> keys() { arr = new ArrayList<>(); for (int i = 0; i < m; i++) { if (keys[i] != null) { arr.add(keys[i]); } } return arr; } }
public static void main(String[] args) { LinearProbeHashST<Integer, String> linearProbeHashST = new LinearProbeHashST<>(); linearProbeHashST.put(12,"12.."); linearProbeHashST.put(2,"2.."); linearProbeHashST.put(34,"34.."); linearProbeHashST.put(17,"17.."); linearProbeHashST.put(55,"55.."); linearProbeHashST.put(214,"214.."); for(Integer i : linearProbeHashST.keys()){ System.out.println(i); } System.out.println("==============================================="); System.out.println(linearProbeHashST.delete(34)); for(Integer i : linearProbeHashST.keys()){ System.out.println(i); } System.out.println("==============================================="); System.out.println(linearProbeHashST.get(55)); } //结果 17 2 34 214 55 12 =============================================== 34.. 17 2 214 55 12 =============================================== 55..
标签:his import NPU 需要 取值 结果 near amp util
原文地址:https://www.cnblogs.com/youzoulalala/p/11125492.html