PAT乙级考试-1001害死人不偿命的3n+1猜想

 1 import java.util.Scanner;
 2 public class Main{
 3     public static void main(String[] args) {
 4         
 5         Scanner input = new Scanner(System.in);
 6         int number = input.nextInt();
 7         int i = 0;
 8        　　　//计算给定的不超出1000的正整数n的3n+1猜想
 9             for (;number != 1;i++){
10                 
11                 if (number % 2 == 0) {
12                     number = number / 2;
13                 }
14                 else {
15                 number = (3 * number + 1) / 2;
16                 }
17                 
18         } 
19             
20         System.out.println(i);
21         }
22     }