C笔试题之编程题四

 1 #include <stdio.h>
 2 
 3 #define uchar unsigned char
 4 
 5 int main(void)
 6 {
 7     uchar square[8][8] = {
 8         { 1, 4, 6, 8, 4, 9, 0, 7 },
 9         { 2, 6, 3, 7, 2, 1, 8, 7 },
10         { 1, 6, 9, 8, 5, 3, 2, 8 },
11         { 4, 5, 7, 2, 1, 2, 8, 3 },
12         { 1, 7, 9, 4, 3, 7, 3, 9 },
13         { 8, 9, 1, 3, 4, 5, 2, 7 },
14         { 6, 8, 4, 3, 2, 9, 7, 3 },
15         { 1, 3, 2, 8, 5, 5, 3, 4 }
16     };
17 
18     uchar sum = 0;
19     uchar min = 144;
20     uchar i, j, k, l, mini, minj;
21 
22     for (i = 0; i < 5; i++)
23         for (j = 0; j < 5; j++)
24         {
25             for (k = i; k < i + 4; k++)
26                 for (l = j; l < j + 4; l++)
27                 {
28                     sum += square[k][l];
29                 }
30             if (sum < min)
31             {
32                 min  = sum;//record minimal value
33                 mini = i;  //record location x,y
34                 minj = j;
35             }
36             sum = 0;
37         }
38     printf("the minimal square4x4 is %d, location x = %d, y = %d.\n", min, mini, minj);
39     getchar();
40 
41     return 0;
42 }