标签:example ecif include div print define while efi main
Given a collection of number segments, you are supposed to recover the smallest number from them. For example, given { 32, 321, 3214, 0229, 87 }, we can recover many numbers such like 32-321-3214-0229-87 or 0229-32-87-321-3214 with respect to different orders of combinations of these segments, and the smallest number is 0229-321-3214-32-87.
Each input file contains one test case. Each case gives a positive integer N (≤) followed by N number segments. Each segment contains a non-negative integer of no more than 8 digits. All the numbers in a line are separated by a space.
For each test case, print the smallest number in one line. Notice that the first digit must not be zero.
5 32 321 3214 0229 87
22932132143287
#include<iostream> #include<cstdio> #include<cmath> #include<cstring> #include<algorithm> #define ll long long #define inf 10000 using namespace std; int cmp(string a,string b) { return a+b<b+a; } int main() { int n,m; string s[inf]; cin>>n; for(int i=0;i<n;i++) cin>>s[i]; sort(s,s+n,cmp); string s1; for(int i=0;i<n;i++) { s1+=s[i]; } //cout<<s1<<" "<<s1[0]<<*s1.begin()<<endl; while(s1[0]==‘0‘&&s1.length()!=0) { s1.erase(s1.begin()); } if(s1.length()==0) cout<<0; cout<<s1; cout<<endl; return 0; }
1038 Recover the Smallest Number string还能这样用 cmp真滴强大
标签:example ecif include div print define while efi main
原文地址:https://www.cnblogs.com/liuzhaojun/p/11166105.html