标签:style blog color io os for sp div on
题意:从a 开始不能到达b,要坐k次电梯的满足条件 :|x - y| < |x - b|. x是当前位置,y是目标位置 的方案数。
每次转移处理个前缀和,然后每次满足条件的和的范围是 :1到 (y+b-1) /2
#include <cstdio> #include <cstring> #include <algorithm> #include <climits> #include <string> #include <iostream> #include <map> #include <cstdlib> #include <list> #include <set> #include <queue> #include <stack> #include <math.h> using namespace std; typedef long long LL; const int maxn = 5555; int dp[maxn][maxn];int sum[maxn][maxn]; const int mod = 1000000000+7; int main() { int n, a, b, k; cin >> n >> a >> b >> k; if (a > b) a = n + 1 - a, b = n + 1 - b; dp[0][a] = 1; for (int i = 1; i <= k; i++){ for (int j = 1; j < b; j++) sum[i-1][j] = sum[i-1][j - 1] + dp[i-1][j],sum[i-1][j]%=mod; for (int j = 1; j < b; j++){ int r= (j+b-1) / 2; dp[i][j] = sum[i - 1][r] - sum[i - 1][0] - dp[i - 1][j]; dp[i][j] = (dp[i][j]+mod) %mod; } } int ans = 0; for (int i = 1; i < b; i++) ans += dp[k][i],ans%=mod; printf("%d\n", ans); return 0; }
CodeForces 274E. Riding in a LiftDp
标签:style blog color io os for sp div on
原文地址:http://www.cnblogs.com/yigexigua/p/4046676.html