标签:math struct pre printf iostream 关键字 problem ref tps
题面:https://www.luogu.org/problemnew/show/P2782
本题可以以南岸或是北岸为关键字先从小到大排序,再在另一岸找最长上升子序列即可。
Code:
#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<cstdlib>
#include<algorithm>
#include<ctime>
using namespace std;
const int N=200005;
int m,b[N],len,d[N];
struct Node{
int n,s;
}a[N];
bool cmp(Node p,Node q){
if(p.n==q.n){
return p.s<q.s;
}
return p.n<q.n;
}
int main(){
scanf("%d",&m);
for(int i=1;i<=m;i++){
scanf("%d%d",&a[i].n,&a[i].s);
}
sort(a+1,a+1+m,cmp);
d[++len]=a[1].s;
for(int i=2;i<=m;i++){
if(a[i].s>d[len]){
d[++len]=a[i].s;
}
else{
int j=upper_bound(d+1,d+1+len,a[i].s)-d;
d[j]=a[i].s;
}
}
printf("%d\n",len);
return 0;
}
标签:math struct pre printf iostream 关键字 problem ref tps
原文地址:https://www.cnblogs.com/ukcxrtjr/p/11194409.html