标签:tom else cto stand pos def forward push case
A number that will be the same when it is written forwards or backwards is known as a Palindromic Number. For example, 1234321 is a palindromic number. All single digit numbers are palindromic numbers.
Although palindromic numbers are most often considered in the decimal system, the concept of palindromicity can be applied to the natural numbers in any numeral system. Consider a number N>0 in base b≥2, where it is written in standard notation with k+1 digits a?i?? as (. Here, as usual, 0 for all i and a?k?? is non-zero. Then N is palindromic if and only if a?i??=a?k−i?? for all i. Zero is written 0 in any base and is also palindromic by definition.
Given any positive decimal integer N and a base b, you are supposed to tell if N is a palindromic number in base b.
Each input file contains one test case. Each case consists of two positive numbers N and b, where 0 is the decimal number and 2 is the base. The numbers are separated by a space.
For each test case, first print in one line Yes
if N is a palindromic number in base b, or No
if not. Then in the next line, print N as the number in base b in the form "a?k?? a?k−1?? ... a?0??". Notice that there must be no extra space at the end of output.
27 2
Yes
1 1 0 1 1
121 5
No
4 4 1
1 #include <iostream> 2 #include <vector> 3 using namespace std; 4 //此处11进制中的10就是10,而不是a 5 int main() 6 { 7 int N, b; 8 cin >> N >> b; 9 vector<int>v1, v2; 10 while (N) 11 { 12 v1.push_back(N%b); 13 N /= b; 14 } 15 v2.assign(v1.rbegin(), v1.rend()); 16 if (v1 == v2) 17 cout << "Yes" << endl; 18 else 19 cout << "No" << endl; 20 if (v2.size() == 0) 21 cout << 0; 22 else 23 { 24 cout << v2[0]; 25 for (int i = 1; i < v2.size(); ++i) 26 cout << " " << v2[i]; 27 } 28 cout << endl; 29 return 0; 30 }
PAT甲级——A1019 General Palindromic Number
标签:tom else cto stand pos def forward push case
原文地址:https://www.cnblogs.com/zzw1024/p/11204290.html