标签:exce turn class mit you because scanf each case
InputThe input file will consist of several cases.
Each case will be presented by an integer n (1<=n<1000000, and n is odd) at first. Following that, n positive integers will be given in a line, all integers will smaller than 2^31. These numbers indicate the card numbers of the presents.n = 0 ends the input.OutputFor each case, output an integer in a line, which is the card number of your present.Sample Input
5
1 1 3 2 2
3
1 2 1
0
Sample Output
3
2
use scanf to avoid Time Limit Exceeded
Hint
Hint
HDU-2095-find your present (2)-位或/STL(set)
标签:exce turn class mit you because scanf each case
原文地址:https://www.cnblogs.com/OFSHK/p/11252837.html