标签:后序遍历 UNC putchar restart har pad || pos ldb
///////////////////////////////////////////////////////////////////////////////////////
// // 9.题目六:重建二叉树
// 题目:输入某二叉树的前序遍历和中序遍历的结果,请重建出改二叉树
struct BinaryTreeNode { int m_iValue; BinaryTreeNode* m_pLeft; BinaryTreeNode* m_pRight; BinaryTreeNode(int iValue = 0, BinaryTreeNode* pLeft = NULL, BinaryTreeNode* pRight = NULL) :m_iValue(iValue), m_pLeft(pLeft), m_pRight(pRight) { } }; BinaryTreeNode* RebuildTree(int* pPreStart, int* pPreEnd, int* pInStart, int* pInEnd) { if (pPreStart > pPreEnd || pInStart > pInEnd) { return NULL; } // 1.建立根节点(前序遍历第一个元素) BinaryTreeNode* pRoot = new BinaryTreeNode(*pPreStart); if (!pRoot) { return NULL; } // 2.找到中序根节点 int* p = pInStart; while (p <= pInEnd && *p != pRoot->m_iValue) { p++; } int iLeftLength = p - pInStart; int* pLeftPreEnd = pPreStart + iLeftLength; // 3.构建左子树 if (iLeftLength > 0) { pRoot->m_pLeft = RebuildTree(pPreStart + 1, pLeftPreEnd, pInStart, p - 1); } // 4.构建右子树 if (iLeftLength < (pPreEnd - pPreStart)) { pRoot->m_pRight = RebuildTree(pLeftPreEnd + 1, pPreEnd, p + 1, pInEnd); } return pRoot; } BinaryTreeNode* RebuildBinaryTree(int* piPreOrderArray, int* piInorderArray, int iLength) { if (NULL == piPreOrderArray || NULL == piInorderArray || iLength <= 0) { return NULL; } return RebuildTree(piPreOrderArray, piPreOrderArray + iLength - 1, piInorderArray, piInorderArray + iLength -1); } void DestroyTree(BinaryTreeNode* pTree) { if (pTree) { // 释放左子树 DestroyTree(pTree->m_pLeft); // 释放右子树 DestroyTree(pTree->m_pRight); delete pTree; pTree = NULL; } } // 后序遍历 void PostTraversal(BinaryTreeNode* pNode) { if (pNode) { PostTraversal(pNode->m_pLeft); PostTraversal(pNode->m_pRight); printf("%02d -> ", pNode->m_iValue); } } void RebuildBinaryTreeTestFunc() { cout << "\n\n --------------- RebuildBinaryTreeTestFunc Start -------------->" << endl; const int MAX_TREE_NODE_COUNT = 8; //前序遍历序列(中 -> 左 -> 右) int aiPreOrderArray[MAX_TREE_NODE_COUNT] = {1, 2, 4, 7, 3, 5, 6, 8}; //中序遍历序列(左 -> 中 -> 右) int aiInorderArray[MAX_TREE_NODE_COUNT] = {4, 7, 2, 1, 5, 3, 8, 6}; //后序遍历序列(左 -> 右 -> 中) int aiPostArray[MAX_TREE_NODE_COUNT] = {7, 4, 2, 5, 8, 6, 3, 1}; BinaryTreeNode* pTree1 = RebuildBinaryTree(aiPreOrderArray, aiInorderArray, MAX_TREE_NODE_COUNT); if (pTree1) { // 后序遍历 PostTraversal(pTree1); putchar(10); // 施法资源 DestroyTree(pTree1); } cout << "\n\n --------------- RebuildBinaryTreeTestFunc End -------------->" << endl; }
标签:后序遍历 UNC putchar restart har pad || pos ldb
原文地址:https://www.cnblogs.com/yzdai/p/11258611.html