水题（三角形与扇形面积计算sin（）应用）

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J - Sincerely

Gym - 101350J

Physics cat likes to draw shapes and figure out their area. He starts by drawing a circle. Then inside the circle, he draws the triangle X, Y, Z - where Y is the center point of the circle, and X and Z touch the circumference of the circle. Please note that points X and Y always have the same x-coordinate.

Given L (the distance between Points X and Y) and A (the angle XYZ in degrees); help physics cat find the shaded area between the right side of the triangle and the circumference of the circle. And when we say help, we mean do all the work for him.

3
1 90
2 180
10 30

0.285398
6.283185
1.179939

注意：sin（）函数接受的是弧度制（用角度除去180）.Π的定义

#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <iostream>
#include <algorithm>
#include <iostream>
#include<cstdio>
#include<string>
#include<cstring>
#include <stdio.h>
#include <string.h>
//#define PI 3.1415926
using namespace std;
const double PI = acos(-1.0);


int main()
{
    int n ;
    cin >> n ;
    while(n--)
    {
        double l , d  , tr , y;
        scanf("%lf%lf" , &l , &d);
        y = l * l * PI ;
        y = d / 360 * y ;
        tr = sin(d /180.0 *PI) * 1 / 2.0 * l * l ;
        printf("%.6lf\n" , y-tr);
    }

    return 0 ;
}

水题（三角形与扇形面积计算sin（）应用）

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原文地址：https://www.cnblogs.com/nonames/p/11290791.html