标签:queue main code second out fine while string bfs
题意:就是求每个点到最近的1的距离,但距离是|xi-x|+|yi-y|。
思路:将每个是1的点BFS全图,想到了就是很水的BFS。
#include<cstdio> #include<cstring> #include<algorithm> #include<vector> #include<map> #include<queue> #define ll long long using namespace std; const int dx[4]={0,0,-1,1},dy[4]={1,-1,0,0}; int n,m; char a[1010][1010]; int b[1010][1010]; queue<pair<int,int> > q; int main() { cin>>n>>m; for(int i=1;i<=n;i++) scanf("%s",a[i]+1); memset(b,-1,sizeof(b)); for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) if(a[i][j]==‘1‘) q.push(make_pair(i,j)),b[i][j]=0; while(q.size()) { pair<int,int> now =q.front(); q.pop(); for(int i=0;i<4;i++) { pair<int,int> next(now.first+dx[i],now.second+dy[i]); if(next.first<1||next.second<1||next.first>n||next.second>m) continue; if(b[next.first][next.second]==-1) { b[next.first][next.second]=b[now.first][now.second]+1; q.push(next);} } } for(int i=1;i<=n;i++) { for(int j=1;j<=m;j++) cout<<b[i][j]<<" "; cout<<endl; } }
标签:queue main code second out fine while string bfs
原文地址:https://www.cnblogs.com/2462478392Lee/p/11291434.html