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217. Contains Duplicate - Easy

时间:2019-08-10 17:40:21      阅读:92      评论:0      收藏:0      [点我收藏+]

标签:and   element   span   cat   function   als   array   new   pac   

Given an array of integers, find if the array contains any duplicates.

Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.

Example 1:

Input: [1,2,3,1]
Output: true

Example 2:

Input: [1,2,3,4]
Output: false

Example 3:

Input: [1,1,1,3,3,4,3,2,4,2]
Output: true

 

use hash table (set)

time = O(n), space = O(n)

class Solution {
    public boolean containsDuplicate(int[] nums) {
        Set<Integer> set = new HashSet<>();
        for(int n : nums) {
            if(!set.add(n)) {
                return true;
            }
        }
        return false;
    }
}

 

217. Contains Duplicate - Easy

标签:and   element   span   cat   function   als   array   new   pac   

原文地址:https://www.cnblogs.com/fatttcat/p/11331893.html

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