整数对

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;

int main()
{
    int T;
    scanf("%d",&T);
    while(T--){
    ll n,m,p;
    scanf("%lld%lld%lld",&n,&m,&p);
    ll t=n/p;
    ll ans=0;
    for(ll r=0;r<=p-1;r++){
        if(r==0){
            ans+=t*m;
        }else if(r<=n%p){
            ans+=(t+1)*(m/(p/__gcd(r,p)));
        }
        else ans+=t*(m/(p/__gcd(r,p)));
    }
        cout<<ans<<‘\n‘;
    }
}