标签:nts int lse des push idt div ports dex
// --- Directions // Given the root node of a tree, return // an array where each element is the width // of the tree at each level. // --- Example // Given: // 0 // / | \ // 1 2 3 // | | // 4 5 // Answer: [1, 3, 2]
function levelWidth(root) { let counts = [0]; let levels = [root, "$end$"]; // [1, 3, 2] // ["e"] while (levels.length > 1) { const current = levels.shift(); if (current === "$end$") { counts[counts.length] = 0; levels.push("$end$"); } else { const { children } = current; for (let node of children) { levels.push(node); } counts[counts.length - 1]++; } } return counts; } module.exports = levelWidth;
Test:
const Node = require(‘./node‘); const levelWidth = require(‘./index‘); test(‘levelWidth is a function‘, () => { expect(typeof levelWidth).toEqual(‘function‘); }); test(‘levelWidth returns number of nodes at widest point‘, () => { const root = new Node(0); root.add(1); root.add(2); root.add(3); root.children[0].add(4); root.children[2].add(5); expect(levelWidth(root)).toEqual([1, 3, 2]); }); test(‘levelWidth returns number of nodes at widest point‘, () => { const root = new Node(0); root.add(1); root.children[0].add(2); root.children[0].add(3); root.children[0].children[0].add(4); expect(levelWidth(root)).toEqual([1, 1, 2, 1]); });
[Algorithm] Tree Width with Level Width
标签:nts int lse des push idt div ports dex
原文地址:https://www.cnblogs.com/Answer1215/p/11336949.html