B - Spreadsheets CodeForces - 1B

#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
#include<cmath>
#include<stack>
#include<cstdlib>
#include<queue>
#include<set>
#include<string.h>
#include<vector>
#include<deque>
#include<map>
using namespace std;
#define INF 0x3f3f3f3f
#define eps 1e-10
#define bug printf("*********\n")
#define debug(x) cout<<#x"=["<<x<<"]" <<endl
typedef long long LL;
typedef long long ll;
const int MAXN = 1e6 + 5;
const int mod = 998244353;

bool is(char a) {
    if(‘A‘ <= a && a <= ‘Z‘)
        return true;
    return false;
}
int check(char *s)
{
    int len = strlen(s);
    int ans = 0,pos1 = -1,pos2 = -1;
    for(int i = 0 ;i < len; i++)
    {
        if(is(s[i]) && s[i] != ‘R‘ && s[i] != ‘C‘)
        {
            ans++;
            continue;
        }
        if(s[i] == ‘R‘) {
            ans ++;
            pos1 = i;
        }
        if(s[i] == ‘C‘) {
            ans++;
            pos2 = i;
        }
    }

    if(ans == 2 && pos1 != -1 && pos2 != -1 && pos2 - pos1 > 1)
        return 1;
    return 2;
}
//将一个数转换为A - Z的进制，比如3 -> C  34 -> AH  123 -> DS
void K(int n)
{
    if(n>26)
        K((n-1)/26);

    printf("%c",(n-1)%26+‘A‘);
}
int main()
{
    int n;
    cin >> n;
    while(n--)
    {
        char s[MAXN];
        scanf("%s",s);
        int flag = check(s);
        //debug(flag);
        if(flag == 1) {
            int len = strlen(s);
            int pos1 = -1,pos2 = -1;
            for(int i = 0 ;i < len; i++)
            {
                if(s[i] == ‘R‘) {
                    pos1 = i;
                }
                if(s[i] == ‘C‘) {
                    pos2 = i;
                }
            }
            int p1 = 0,p2 = 0;
            for(int i = pos1 + 1; i < pos2; i++) {
                p1 *= 10;
                p1 += (s[i] - ‘0‘);
            }
            for(int i = pos2 + 1; i < len; i++) {
                p2 *= 10;
                p2 += (s[i] - ‘0‘);
            }
            char ch = ‘A‘;
            K(p2);
            printf("%d\n",p1);
        } else {
            int p1 = 0,p2 = 0;
            int len = strlen(s);
            int i;
            for(i = 0; i < len; i++) {
                if(is(s[i])) {
                    p1 *= 26;
                    p1 += s[i] - ‘A‘ + 1;
                }
                else
                    break;
            }

            for(i ; i < len ; i++) {
                p2 *= 10;
                p2 += s[i] - ‘0‘;
            }
            printf("R%dC%d\n",p2,p1);
        }
    }
}