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os模块

一、导入方式

import os

二、作用

与操作系统交互，可以操控文件

三、模块功能

3.1 经常使用

os.listdir():列出所有文件

print(os.listdir())   #列出所有文件
----------------------------------------------------------
['12.txt', '123', 'a.txt', 'access.log', 'db.txt', 'db.txt.swap', 'LeetCode.py']

os.rename() :重命名
os.remove() :删除

os.rename('m2.py','m1.py')  #重命名m2.py
os.remove('m2.py')  #删除m2.py
--------------------------------------------------------------

os.path.join():拼接文件路径(支持不同平台)

res = os.path.join(r'E:\python上海学习\02上课认真听讲\老师讲的内容\0816\04 os模块.py','m5.py') # 拼接文件路径
res = os.path.join(r'E:\python上海学习\02上课认真听讲\老师讲的内容\0816\04 os模块.py'm5','test.py') 
# 拼接多个文件路径
-------------------------------------------------------------

os.path.abspath（）：返回文件规范化的绝对路径

os.path.abspath(__file__)  #返回文件的绝对路径
os.path.dirname(os.path.dirname(os.path.abspath(__file__))) #返回文件的上级目录的路径

3.1 一般使用

import os
g = os.walk(r'绝对路径。。。。')  # 返回三个值，第一个值是路径；第二个值是路径下的文件夹，第三个值是路径下的文件
for i in g:
    print(i)

四、计算函数代码

import os
import sys


def count_code(path):  # path == '文件的绝对路径'
    count = 0
    flag = True

    if os.path.isdir(path):
        for dir, _, file_path_list in os.walk(path):
            for file_path in file_path_list:
                try:
                    file_path = os.path.join(dir, file_path)
                    path_list = file_path.split('.')
                    file_count = 0
                    if path_list[-1] == 'py':
                        with open(file_path, 'r', encoding='utf8') as fr:
                            for line in fr:
                                if (line.startswith('\'\'\'') or line.startswith('\"\"\"')) and flag:
                                    flag = False
                                    continue
                                elif ('=' in line and ('\'\'\'' in line or '\"\"\"' in line)) and flag:
                                    flag = False
                                    continue
                                elif (line.startswith('\'\'\'') or line.startswith('\"\"\"')) and not flag:
                                    flag = True
                                    continue

                                if line.startswith('#') and flag:
                                    continue
                                elif line == '\n' and flag:
                                    continue
                                elif flag:
                                    count += 1
                                    file_count += 1
                    print(f'{file_path}有{file_count}行')
                except Exception:
                    print(f'该文件{file_path}有问题')
                    continue

    elif os.path.isfile(path):
        path_list = path.split('.')
        if path_list[-1] == 'py':
            file_count = 0
            with open(path, 'r', encoding='utf8') as fr:
                for line in fr:
                    if (line.startswith('\'\'\'') or line.startswith('\"\"\"')) and flag:
                        flag = False
                        continue
                    elif ('=' in line and ('\'\'\'' in line or '\"\"\"' in line)) and flag:
                        flag = False
                        continue
                    elif (line.startswith('\'\'\'') or line.startswith('\"\"\"')) and not flag:
                        flag = True
                        continue
                    if line.startswith('#') and flag:
                        continue
                    elif line == '\n' and flag:
                        continue
                    elif flag:
                        count += 1
                        file_count += 1
            print(f'{path}有{file_count}行')
        else:
            print('不是py文件')

    return count


if __name__ == '__main__':
    # file_path = sys.argv[1]
    # count = count_code(file_path)
    count = count_code('文件（文件夹）绝对路径')
    print(count)

os模块

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原文地址：https://www.cnblogs.com/yanjiayi098-001/p/11366069.html