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前端 玫瑰花小样式

时间:2019-08-20 12:47:17      阅读:92      评论:0      收藏:0      [点我收藏+]

标签:++   math   链接   fill   sha   效果图   bsp   parse   idt   

原文链接:https://www.cnblogs.com/xiaoguan-bky/p/11195945.html  (若侵请联系)

代码:

html>

<head>
    <title>Rose making and sharing(玫瑰花)</title>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
</head>

<body style="margin-left:200px">
    <div style="text-align: center">
        <canvas id="c"></canvas>
    </div>
    <h1>Looking forward to more exchanges and sharing(玫瑰花)</h1>
    <script type="text/javascript">
    var canvas = document.getElementsByTagName(canvas)[0];
    var context = canvas.getContext(2d);

    var a = context;
    var b = document.body;
    var c = canvas;

    document.body.clientWidth;
    var zBuffer = [];
    var SIZE = 777;
    canvas.width = canvas.height = SIZE;
    var h = -350;

    function surface(a, b, c) {
        if (c > 60) {
            return {
                x: Math.sin(a * 7) * (13 + 5 / (.2 + Math.pow(b * 4, 4))) - Math.sin(b) * 50,
                y: b * SIZE + 50,
                z: 625 + Math.cos(a * 7) * (13 + 5 / (.2 + Math.pow(b * 4, 4))) + b * 400,
                r: a * 1 - b / 2,
                g: a
            };
        }

        var A = a * 2 - 1;
        var B = b * 2 - 1;

        if (A * A + B * B < 1) {
            if (c > 37) {
                var j = c & 1;
                var n = j ? 6 : 4;
                var o = .5 / (a + .01) + Math.cos(b * 125) * 3 - a * 300;
                var w = b * h;
                return {
                    x: o * Math.cos(n) + w * Math.sin(n) + j * 610 - 390,
                    y: o * Math.sin(n) - w * Math.cos(n) + 550 - j * 350,
                    z: 1180 + Math.cos(B + A) * 99 - j * 300,
                    r: .4 - a * .1 + Math.pow(1 - B * B, -h * 6) * .15 - a * b * .4 + Math.cos(a + b) / 5 + Math.pow(Math.cos((o * (a + 1) + (B > 0 ? w : -w)) / 25), 30) * .1 * (1 - B * B),
                    g: o / 1e3 + .7 - o * w * 3e-6
                };
            }

            if (c > 32) {
                c = c * 1.16 - .15;
                var o = a * 45 - 20;
                var w = b * b * h;
                var z = o * Math.sin(c) + w * Math.cos(c) + 620;
                return {
                    x: o * Math.cos(c) - w * Math.sin(c),
                    y: 28 + Math.cos(B * .5) * 99 - b * b * b * 60 - z / 2 - h,
                    z: z,
                    r: (b * b * .3 + Math.pow((1 - (A * A)), 7) * .15 + .3) * b,
                    g: b * .7
                };
            }

            var o = A * (2 - b) * (80 - c * 2);
            var w = 99 - Math.cos(A) * 120 - Math.cos(b) * (-h - c * 4.9) + Math.cos(Math.pow(1 - b, 7)) * 50 + c * 2;
            var z = o * Math.sin(c) + w * Math.cos(c) + 700;
            return {
                x: o * Math.cos(c) - w * Math.sin(c),
                y: B * 99 - Math.cos(Math.pow(b, 7)) * 50 - c / 3 - z / 1.35 + 450,
                z: z,
                r: (1 - b / 1.2) * .9 + a * .1,
                g: Math.pow((1 - b), 20) / 4 + .05
            };
        }
    }



    setInterval(function() {
        for (var i = 0; i < 10000; i++) {
            var part = i % 46;
            var c = part / .74;
            var point = surface(Math.random(), Math.random(), c);
            if (point) {
                var z = point.z;
                var x = parseInt(point.x * SIZE / z - h);
                var y = parseInt(point.y * SIZE / z - h);
                var zBufferIndex = y * SIZE + x;
                if ((typeof zBuffer[zBufferIndex] === "undefined") || (zBuffer[zBufferIndex] > z)) {
                    zBuffer[zBufferIndex] = z;
                    var r = -parseInt(point.r * h);
                    var g = -parseInt(point.g * h);
                    var b = -parseInt(point.r * point.r * -80);
                    context.fillStyle = "rgb(" + r + "," + g + "," + b + ")";
                    context.fillRect(x, y, 1, 1);
                }
            }
        }
    }, 0);
    </script>
</body>

</html>

效果图:

技术图片

 

前端 玫瑰花小样式

标签:++   math   链接   fill   sha   效果图   bsp   parse   idt   

原文地址:https://www.cnblogs.com/houBlogs/p/11382036.html

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