标签:++ math 链接 fill sha 效果图 bsp parse idt
原文链接:https://www.cnblogs.com/xiaoguan-bky/p/11195945.html (若侵请联系)
代码:
html> <head> <title>Rose making and sharing(玫瑰花)</title> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> </head> <body style="margin-left:200px"> <div style="text-align: center"> <canvas id="c"></canvas> </div> <h1>Looking forward to more exchanges and sharing(玫瑰花)</h1> <script type="text/javascript"> var canvas = document.getElementsByTagName(‘canvas‘)[0]; var context = canvas.getContext(‘2d‘); var a = context; var b = document.body; var c = canvas; document.body.clientWidth; var zBuffer = []; var SIZE = 777; canvas.width = canvas.height = SIZE; var h = -350; function surface(a, b, c) { if (c > 60) { return { x: Math.sin(a * 7) * (13 + 5 / (.2 + Math.pow(b * 4, 4))) - Math.sin(b) * 50, y: b * SIZE + 50, z: 625 + Math.cos(a * 7) * (13 + 5 / (.2 + Math.pow(b * 4, 4))) + b * 400, r: a * 1 - b / 2, g: a }; } var A = a * 2 - 1; var B = b * 2 - 1; if (A * A + B * B < 1) { if (c > 37) { var j = c & 1; var n = j ? 6 : 4; var o = .5 / (a + .01) + Math.cos(b * 125) * 3 - a * 300; var w = b * h; return { x: o * Math.cos(n) + w * Math.sin(n) + j * 610 - 390, y: o * Math.sin(n) - w * Math.cos(n) + 550 - j * 350, z: 1180 + Math.cos(B + A) * 99 - j * 300, r: .4 - a * .1 + Math.pow(1 - B * B, -h * 6) * .15 - a * b * .4 + Math.cos(a + b) / 5 + Math.pow(Math.cos((o * (a + 1) + (B > 0 ? w : -w)) / 25), 30) * .1 * (1 - B * B), g: o / 1e3 + .7 - o * w * 3e-6 }; } if (c > 32) { c = c * 1.16 - .15; var o = a * 45 - 20; var w = b * b * h; var z = o * Math.sin(c) + w * Math.cos(c) + 620; return { x: o * Math.cos(c) - w * Math.sin(c), y: 28 + Math.cos(B * .5) * 99 - b * b * b * 60 - z / 2 - h, z: z, r: (b * b * .3 + Math.pow((1 - (A * A)), 7) * .15 + .3) * b, g: b * .7 }; } var o = A * (2 - b) * (80 - c * 2); var w = 99 - Math.cos(A) * 120 - Math.cos(b) * (-h - c * 4.9) + Math.cos(Math.pow(1 - b, 7)) * 50 + c * 2; var z = o * Math.sin(c) + w * Math.cos(c) + 700; return { x: o * Math.cos(c) - w * Math.sin(c), y: B * 99 - Math.cos(Math.pow(b, 7)) * 50 - c / 3 - z / 1.35 + 450, z: z, r: (1 - b / 1.2) * .9 + a * .1, g: Math.pow((1 - b), 20) / 4 + .05 }; } } setInterval(function() { for (var i = 0; i < 10000; i++) { var part = i % 46; var c = part / .74; var point = surface(Math.random(), Math.random(), c); if (point) { var z = point.z; var x = parseInt(point.x * SIZE / z - h); var y = parseInt(point.y * SIZE / z - h); var zBufferIndex = y * SIZE + x; if ((typeof zBuffer[zBufferIndex] === "undefined") || (zBuffer[zBufferIndex] > z)) { zBuffer[zBufferIndex] = z; var r = -parseInt(point.r * h); var g = -parseInt(point.g * h); var b = -parseInt(point.r * point.r * -80); context.fillStyle = "rgb(" + r + "," + g + "," + b + ")"; context.fillRect(x, y, 1, 1); } } } }, 0); </script> </body> </html>
效果图:
标签:++ math 链接 fill sha 效果图 bsp parse idt
原文地址:https://www.cnblogs.com/houBlogs/p/11382036.html