标签：strong test less eve rip multiple gre and accept
Big Event in HDU
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 57986 Accepted Submission(s): 19484
Problem Description
Nowadays,
we all know that Computer College is the biggest department in HDU.
But, maybe you don‘t know that Computer College had ever been split into
Computer College and Software College in 2002.
The splitting is
absolutely a big event in HDU! At the same time, it is a trouble thing
too. All facilities must go halves. First, all facilities are assessed,
and two facilities are thought to be same if they have the same value.
It is assumed that there is N (0<N<1000) kinds of facilities
(different value, different kinds).
Input
Input
contains multiple test cases. Each test case starts with a number N (0
< N <= 50 -- the total number of different facilities). The next N
lines contain an integer V (0<V<=50 --value of facility) and an
integer M (0<M<=100 --corresponding number of the facilities)
each. You can assume that all V are different.
A test case starting with a negative integer terminates input and this test case is not to be processed.
Output
For
each case, print one line containing two integers A and B which denote
the value of Computer College and Software College will get
respectively. A and B should be as equal as possible. At the same time,
you should guarantee that A is not less than B.
Sample Input
2
10 1
20 1
3
10 1
20 2
30 1
-1
Sample Output
题目大意与分析
给出一堆东西的重量和个数，要尽可能的将物品分成重量接近的两堆A和B,且A的重量不小于B
求以sum/2为容量的背包即可，求出来的值就是B sum减去B就是A
代码
#include <bits/stdc++.h>
using namespace std;
int val[5005];
int dp[255555];
int main()
{
int n,i,j,a,b,l,sum;
while(~scanf("%d",&n),n>0)
{
memset(val,0,sizeof(val));
memset(dp,0,sizeof(dp));
l = 0;
sum = 0;
for(i = 0;i<n;i++)
{
scanf("%d%d",&a,&b);
while(b--)
{
val[l++] = a;
sum+=a;
}
}
for(i = 0;i<l;i++)
{
for(j = sum/2;j>=val[i];j--)
{
dp[j] = max(dp[j],dp[j-val[i]]+val[i]);
}
}
printf("%d %d\n",sum-dp[sum/2],dp[sum/2]);
}
return 0;
}
HDU 1171 Big Event in HDU （动态规划、01背包）
标签：strong test less eve rip multiple gre and accept
原文地址：https://www.cnblogs.com/dyhaohaoxuexi/p/11396939.html
