标签:cpp unsigned next 网络 return namespace const tmp pop
先存一下几个较难题的AC代码:
1002:
#include<bits/stdc++.h> using namespace std; #define fi first #define se second const int maxn=15000000; const int N=110000; int T; int n,m; int sum[maxn],pos,a[N]; struct node { int ll,rr; }tr[maxn]; pair<int,int> b[N]; map<int,int> idx; set<int> del_nums; set<int>::iterator it; int f[N]; inline int lowbit(int x) { return x&-x; } int root1[N],root2[N],pp[N]; int copy(int x) { ++pos; sum[pos]=sum[x]; tr[pos].ll=tr[x].ll; tr[pos].rr=tr[x].rr; return pos; } void add(int k,int l,int r,int x) { sum[k]++; if (l==r) return; int mid=(l+r)/2; if (x<=mid) { tr[k].ll=copy(tr[k].ll); add(tr[k].ll,l,mid,x); } else { tr[k].rr=copy(tr[k].rr); add(tr[k].rr,mid+1,r,x); } } int ask(int k,int l,int r,int x) { if (sum[k]==0) return n+1; if (l==r) return l; int mid=(l+r)/2; if (l>=x) { if (sum[tr[k].ll]) return ask(tr[k].ll,l,mid,x); else return ask(tr[k].rr,mid+1,r,x); } else { int res; if (mid<x) res=n+1; else res=ask(tr[k].ll,l,mid,x); if (res==n+1) return ask(tr[k].rr,mid+1,r,x); else return res; } } int main() { scanf("%d",&T); while (T--) { scanf("%d %d",&n,&m); for (int i=1;i<=n;i++) scanf("%d",&a[i]),b[i].fi=a[i],b[i].se=i,pp[i]=0; sort(b+1,b+1+n); reverse(b+1,b+1+n); idx.clear(); for (int i=1;i<=n;i++) idx[a[i]]=i; for (int i=1;i<=n;i++) { if (i>1&&b[i].fi+1==b[i-1].fi) f[b[i].se]=f[b[i-1].se]; else f[b[i].se]=b[i].fi; } pos=0; root2[n+1]=copy(0); for (int i=n;i>=1;i--) { root2[i]=copy(root2[i+1]); add(root2[i],1,n,a[i]); } int lastans=0; del_nums.clear(); del_nums.insert(n+1); while (m--) { int op,x,r,k; scanf("%d",&op); if (op==1) { scanf("%d",&x); x=x^lastans; if (!pp[x]) { int tmp=x; pp[x]=1; del_nums.insert(a[x]); idx.erase(a[x]); } } else { scanf("%d %d",&r,&k); r=r^lastans; k=k^lastans; if (!idx.count(k)||idx[k]>r) printf("%d\n",k),lastans=k; else { int pos=idx[k]; int x=f[pos]; int y; if (r==n) y=n+1; else y=ask(root2[r+1],1,n,k); it=del_nums.lower_bound(k); int z=*it; lastans=min(x,min(y-1,z-1))+1; printf("%d\n",lastans); } } } } return 0; }
1005:
#include<bits/stdc++.h> #define ll long long using namespace std; const int maxn = 1e6+10; const ll mod = 1e9+7; const ll inv2 = 5e8+4; const ll inv6 = 166666668; int prime[maxn], phi[maxn]; ll sum[maxn]; bool vis[maxn]; int cnt = 0; void init() { phi[1] = 1; for(int i = 2; i < maxn; i++) { if(!vis[i]) prime[++cnt] = i, phi[i] = i-1;; for(int j = 1; j <= cnt && i*prime[j] < maxn; j++) { vis[i*prime[j]] = true; if(i%prime[j] == 0) { phi[i*prime[j]] = phi[i]*prime[j]; break; } else phi[i*prime[j]] = phi[i]*(prime[j]-1); } } sum[0] = 0; for(int i = 1; i < maxn; i++) { sum[i] = (sum[i-1]+1ll*i*phi[i])%mod; } } unordered_map<ll, ll> mp; ll one(ll n) { n %= mod; return n*(n+1)%mod*inv2%mod; } ll squ(ll n) { n %= mod; return n*(n+1)%mod*((2*n+1)%mod)%mod*inv6%mod; } ll F(ll n) { if(n < maxn) return sum[n]; if(mp.count(n)) return mp[n]; ll res = squ(n); for(ll l = 2, r; l <= n; l = r+1) { r = n/(n/l); ll tmp = (one(r)-one(l-1)+mod)%mod; res -= tmp*F(n/l)%mod; if(res < 0) res += mod; } return mp[n] = res; } int main() { init(); int T; scanf("%d", &T); while(T--) { ll n, a, b; scanf("%lld%lld%lld", &n, &a, &b); ll tmp = F(n); ll ans = (tmp+1)*inv2%mod; ans = (ans-1+mod)%mod; printf("%lld\n", (ans%mod+mod)%mod); } return 0; }
1008:
#pragma GCC optimize("Ofast") #include<bits/stdc++.h> #define ll long long #define ull unsigned long long #define fi first #define se second #define mp make_pair #define pii pair<ll,ll> #define all(x) x.begin(),x.end() #define IO ios::sync_with_stdio(false);cin.tie(0);cout.tie(0) #define rep(ii,a,b) for(int ii=a;ii<=b;++ii) #define per(ii,a,b) for(int ii=b;ii>=a;--ii) #define forn(i,x,g,e) for(int i=g[x];i;i=e[i].next) #define show(x) cout<<#x<<"="<<x<<endl #define showa(a,b) cout<<#a<<‘[‘<<b<<"]="<<a[b]<<endl #define show2(x,y) cout<<#x<<"="<<x<<" "<<#y<<"="<<y<<endl #define show3(x,y,z) cout<<#x<<"="<<x<<" "<<#y<<"="<<y<<" "<<#z<<"="<<z<<endl #define show4(w,x,y,z) cout<<#w<<"="<<w<<" "<<#x<<"="<<x<<" "<<#y<<"="<<y<<" "<<#z<<"="<<z<<endl #define show5(v,w,x,y,z) cout<<#v<<"="<<v<<" "<<#w<<"="<<w<<" "<<#x<<"="<<x<<" "<<#y<<"="<<y<<" "<<#z<<"="<<z<<endl #define showmm(x,a,b) rep(i,0,a) rep(j,0,b) cout<<#x<<‘[‘<<i<<‘]‘<<‘[‘<<j<<"]="<<x[i][j]<<(" \n"[j==b]) #define showm(x,a,b) rep(i,0,a) rep(j,0,b) cout<<x[i][j]<<(" \n"[j==b]) #define showa1(x,a,b) rep(i,a,b) showa(x,i);cout<<endl #define showa2(x,a,b) rep(i,a,b) cout<<x[i]<<‘ ‘;cout<<endl using namespace std; const int maxn=1e5+10,maxm=3e5+10; const ll INF=0x3f3f3f3f,mod=1e9+7; int casn,n,m,k,cnt = 1; priority_queue<int> que; int main() { IO; cin>>casn; while (casn--) { cin >>n>>k; cnt=1; ll sum=k; while(!que.empty()) que.pop(); rep(i,1,n){ ll tmp=0; cin>>tmp; cnt+=tmp/k; sum+=tmp; if (tmp%k)que.push(tmp%k); } rep(i,cnt,n-1) { sum+=k-que.top(); que.pop(); } cout<<sum<<endl; } return 0; }
标签:cpp unsigned next 网络 return namespace const tmp pop
原文地址:https://www.cnblogs.com/nervendnig/p/11403247.html