码迷,mamicode.com
首页 > 其他好文 > 详细

P1220-关路灯

时间:2019-08-26 13:09:11      阅读:62      评论:0      收藏:0      [点我收藏+]

标签:ret   getch   put   code   _for   char   while   col   getchar   

 1 #include <bits/stdc++.h>
 2 #define _for(i,a,b) for(int i = (a);i < b;i ++)
 3 #define _rep(i,a,b) for(int i = (a);i > b;i --)
 4 #define INF 0x3f3f3f3f
 5 #define MOD 1000000007
 6 typedef long long ll;
 7 using namespace std;
 8 inline ll read()
 9 {
10     ll ans = 0;
11     char ch = getchar(), last =  ;
12     while(!isdigit(ch)) last = ch, ch = getchar();
13     while(isdigit(ch)) ans = (ans << 1) + (ans << 3) + ch - 0, ch = getchar();
14     if(last == -) ans = -ans;
15     return ans;
16 }
17 inline void write(ll x)
18 {
19     if(x < 0) x = -x, putchar(-);
20     if(x >= 10) write(x / 10);
21     putchar(x % 10 + 0);
22 }
23 struct lamp
24 {
25     int pos;
26     int power;
27 };
28 int n,c;
29 lamp a[53];
30 int dp[53][53][2];
31 int sum[53][53];
32 int main()
33 {
34     n = read(), c = read();
35     _for(i,1,n+1)
36         a[i].pos = read(),a[i].power = read();
37 
38     _for(i,1,n+1)
39     {
40         sum[i][i] = a[i].power;
41         _for(j,i+1,n+1)
42             sum[i][j] = sum[i][j-1]+a[j].power;
43     }
44 
45     memset(dp,0x3f,sizeof(dp));
46     if(c>=2)
47         dp[c-1][c][0] = (a[c].pos-a[c-1].pos)*(sum[1][c-1]+sum[c+1][n]);
48     if(c<=n-1)
49         dp[c][c+1][1] = (a[c+1].pos-a[c].pos)*(sum[1][c-1]+sum[c+1][n]);
50 
51     _for(len,3,n+1)
52         _for(l,1,n-len+2)
53         {
54             int r = l+len-1;
55             dp[l][r][0] = min(dp[l+1][r][0]+(a[l+1].pos-a[l].pos)*(sum[1][l]+sum[r+1][n])
56             ,dp[l+1][r][1]+(a[r].pos-a[l].pos)*(sum[1][l]+sum[r+1][n]));
57             dp[l][r][1] = min(dp[l][r-1][0]+(a[r].pos-a[l].pos)*(sum[1][l-1]+sum[r][n])
58             ,dp[l][r-1][1]+(a[r].pos-a[r-1].pos)*(sum[1][l-1]+sum[r][n]));
59         }
60     write(min(dp[1][n][0],dp[1][n][1]));
61     return 0;
62 }

 

P1220-关路灯

标签:ret   getch   put   code   _for   char   while   col   getchar   

原文地址:https://www.cnblogs.com/Asurudo/p/11411863.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!