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(Easy) Reverse linked list LeetCode

时间:2019-08-27 19:33:14      阅读:58      评论:0      收藏:0      [点我收藏+]

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Description:

Reverse a singly linked list.

Example:

Input: 1->2->3->4->5->NULL
Output: 5->4->3->2->1->NULL

Follow up:

A linked list can be reversed either iteratively or recursively. Could you implement both?

Accepted
661,364
Submissions
1,172,734

 

Solution:

 

  Explanation:

Iterative Method

    1. Initialize three pointers prev as NULL, curr as head and next as NULL.
    2. Iterate trough the linked list. In loop, do following.
      // Before changing next of current,
      // store next node
      next = curr->next

      // Now change next of current
      // This is where actual reversing happens
      curr->next = prev

      // Move prev and curr one step forward
      prev = curr
      curr = next

 

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
    public ListNode reverseList(ListNode head) {
        
        ListNode prev =null, curr = head, next = null;
        
        
        while(curr!=null){
            
            
             next = curr.next; 
            
             curr.next = prev;
            
             prev = curr; 
            
             curr = next;
        }
        
        
        return prev;
        
        
    }
}

 

 

技术图片

 

 

 

 

 

 

 

 

 

 

 

    

(Easy) Reverse linked list LeetCode

标签:alt   tor   script   src   nbsp   ssi   node   follow   png   

原文地址:https://www.cnblogs.com/codingyangmao/p/11419928.html

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