标签：har 存在 test you 注意 fonts nowrap return std
This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.
Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student‘s name, gender, ID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F(female) or M (male), and grade is an integer between 0 and 100. It is guaranteed that all the grades are distinct.
For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference grade?F??−grade?M??. If one such kind of student is missing, output Absent in the corresponding line, and output NA in the third line instead.
3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95
Mary EE990830
Joe Math990112
6
1
Jean M AA980920 60
Absent
Jean AA980920
NA
题解：
要注意absent的顺序
题目大意： 给N个学生的成绩、名字、ID和分数，还有性别（gender）。分别找出男孩子分数最低和女孩子分数最高的，打印名字和ID，然后求两者的成绩差，如果某一方不存在，那么打印Absent，分数差值为NA。
AC代码：
#include<bits/stdc++.h> using namespace std; string nm; char ge; string id; int grade; int n; int main(){ int n; cin>>n; string fn="",mn=""; string fid,mid; int fg=-1,mg=101; for(int i=1;i<=n;i++) { cin>>nm>>ge>>id>>grade; if(ge==‘F‘){ if(grade>fg){ fg=grade; fn=nm; fid=id; } } if(ge==‘M‘){ if(grade<mg){ mg=grade; mn=nm; mid=id; } } } if(fg<0){ cout<<"Absent"<<endl;//注意absent的顺序 cout<<mn<<" "<<mid<<endl; cout<<"NA"; } else if(mg>100){ cout<<fn<<" "<<fid<<endl; cout<<"Absent"<<endl;//注意absent的顺序 cout<<"NA"<<endl; }else{ cout<<fn<<" "<<fid<<endl; cout<<mn<<" "<<mid<<endl; cout<<fg-mg<<endl; } return 0; }
PAT 甲级 1036 Boys vs Girls (25 分)（简单题）
标签：har 存在 test you 注意 fonts nowrap return std
原文地址：https://www.cnblogs.com/caiyishuai/p/11420731.html
