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Remove Duplicates from sorted array

时间:2019-09-03 00:15:28      阅读:122      评论:0      收藏:0      [点我收藏+]

标签:type   ast   other   bsp   locate   should   ++i   cat   must   

Given a sorted array, remove the duplicates in place such that each element appear only once
and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
For example, Given input array A = [1,1,2],
Your function should return length = 2, and A is now [1,2]

//code1:
O(n),O(1)
class Solution{
    public:
        int removeDuplicates(vector<int>& nums){
            if(nums.empty()) return 0;
            
            int index = 0;
            for(int i = 1; i < nums.size(); ++i){
                if(nums[index] != nums[i])
                    nums[++index] = nums[i];
            }
            
            return index + 1;
        }
};


//code2:
class Solution{
    public:
        int removeDuplicates(vector<int>& nums){
            return distance(nums.begin(),unique(nums.begin(),nums.end()));
        }
};

//code3:
class Solution{
    public:
        int removeDuplicates(vector<int>& nums){
            return distance(nums.begin(),removeDuplicates(nums.begin(),nums.end(),nums.begin()));
        }
    
    template<typename InIt, typename OutIt>
    OutIt removeDuplicates(InIt first,InIt last, OutIt output){
        while(first != last){
            *output++ = *first;
            first = upper_bound(first,last,*first);
        }
        return output;
    }
};

 

Remove Duplicates from sorted array

标签:type   ast   other   bsp   locate   should   ++i   cat   must   

原文地址:https://www.cnblogs.com/hujianglang/p/11449809.html

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