码迷,mamicode.com
首页 > 其他好文 > 详细

leetcode - Text Justification

时间:2014-10-26 17:05:25      阅读:175      评论:0      收藏:0      [点我收藏+]

标签:style   color   io   os   ar   for   sp   div   on   

Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified.

You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ‘ ‘ when necessary so that each line has exactlyL characters.

Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.

For the last line of text, it should be left justified and no extra space is inserted between words.

For example,
words["This", "is", "an", "example", "of", "text", "justification."]
L16.

Return the formatted lines as:

[
   "This    is    an",
   "example  of text",
   "justification.  "
]

Note: Each word is guaranteed not to exceed L in length.

class Solution {
public:
    std::vector<std::string> fullJustify(std::vector<std::string> &words, int L) {
		std::vector<std::string> res;
		for(int i = 0, k, l; i < words.size(); i += k) 
		{
			for(k = l = 0; i + k < words.size() && l + words[i+k].size() <= L - k; k++) 
			{
				l += words[i+k].size();
			}
			std::string tmp = words[i];
			for(int j = 0; j < k - 1; j++) 
			{
				if(i + k >= words.size()) tmp += " ";
				else tmp += std::string((L - l) / (k - 1) + (j < (L - l) % (k - 1)), ' ');
				tmp += words[i+j+1];
			}
			tmp += std::string(L - tmp.size(), ' ');
			res.push_back(tmp);
		}
		return res;
	}
};


leetcode - Text Justification

标签:style   color   io   os   ar   for   sp   div   on   

原文地址:http://blog.csdn.net/akibatakuya/article/details/40477173

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!