标签：nta contain mission Once esc char otherwise div character
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.
Each letter in the magazine string can only be used once in your ransom note.
Note:
You may assume that both strings contain only lowercase letters.
canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true
class Solution { public boolean canConstruct(String ransomNote, String magazine) { if((magazine==null|| magazine.length()==0)&&(ransomNote==null || ransomNote.length()==0)){ return true; } if(ransomNote==null||ransomNote.length()==0){ return true; } for(int i = 0; i < ransomNote.length(); i++){ if(Count(ransomNote, ransomNote.charAt(i)) > Count(magazine, ransomNote.charAt(i))){ return false; } } return true; } static int Count(String str, Character a){ int count = 0; for(int i = 0; i < str.length(); i++){ if(str.charAt(i)==a){ count++; } } return count; } }
标签：nta contain mission Once esc char otherwise div character
原文地址：https://www.cnblogs.com/codingyangmao/p/11495871.html
