74. Search a 2D Matrix

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Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

• Integers in each row are sorted from left to right.
• The first integer of each row is greater than the last integer of the previous row.

Example 1:

Input:
matrix = [
  [1,   3,  5,  7],
  [10, 11, 16, 20],
  [23, 30, 34, 50]
]
target = 3
Output: true

Example 2:

Input:
matrix = [
  [1,   3,  5,  7],
  [10, 11, 16, 20],
  [23, 30, 34, 50]
]
target = 13
Output: false

class Solution {
    public boolean searchMatrix(int[][] matrix, int target) {
        if(matrix.length == 0) return false;
        int m = matrix[0].length;
        int n = matrix.length;
        int left = 0;
        int right = m * n - 1;
        while(left <= right){
            int mid = left + (right - left)/2;
            int value = matrix[mid/m][mid%m];
            if(target == value) return true;
            else if(target < value) right = mid - 1;
            else left = mid + 1;
        }
        return false;
    }
}

把matrix想象成sorted list，直接用二分法搜索即可，对应的坐标是关键

74. Search a 2D Matrix

标签：arch   last   sort   algo   algorithm   rom   example   list   bsp   

原文地址：https://www.cnblogs.com/wentiliangkaihua/p/11511268.html