Codeforces 750 E New Year and Old Subsequence

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E. New Year and Old Subsequence
思路：线段树维护矩阵乘法。
代码：

#pragma GCC optimize(2)
#pragma GCC optimize(3)
#pragma GCC optimize(4)
#include<bits/stdc++.h>
using namespace std;
#define y1 y11
#define fi first
#define se second
#define pi acos(-1.0)
#define LL long long
//#define mp make_pair
#define pb emplace_back
#define ls rt<<1, l, m
#define rs rt<<1|1, m+1, r
#define ULL unsigned LL
#define pll pair<LL, LL>
#define pli pair<LL, int>
#define pii pair<int, int>
#define piii pair<pii, int>
#define pdd pair<double, double>
#define mem(a, b) memset(a, b, sizeof(a))
#define debug(x) cerr << #x << " = " << x << "\n";
#define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
//head

const int INF = 0x3f3f3f3f;
const int N = 2e5 + 10;
struct Matrix {
    int a[5][5];
    inline void init() {
        memset(a, INF, sizeof a);
    }
    inline Matrix operator * (const Matrix & rhs) const {
        Matrix res;
        res.init();
        for (int k = 0; k < 5; ++k) {
            for (int i = 0; i < 5; ++i) {
                for (int j = 0; j < 5; ++j) {
                    res.a[i][j] = min(res.a[i][j], a[i][k]+rhs.a[k][j]);
                }
            }
        }
        return res;
    }
}tree[N<<2];

char s[N];
int n, q, l, r;
inline int push_up(int rt) {
    tree[rt] = tree[rt<<1]*tree[rt<<1|1];
}
/* |2|0|1|7| */
void build(int rt, int l, int r) {
    if(l == r) {
        tree[rt].init();
        for (int i = 0; i < 5; ++i) tree[rt].a[i][i] = 0;
        if(s[l] == '2') tree[rt].a[0][1] = 0, tree[rt].a[0][0] = 1;
        else if(s[l] == '0') tree[rt].a[1][2] = 0, tree[rt].a[1][1] = 1;
        else if(s[l] == '1') tree[rt].a[2][3] = 0, tree[rt].a[2][2] = 1;
        else if(s[l] == '7') tree[rt].a[3][4] = 0, tree[rt].a[3][3] = 1;
        else if(s[l] == '6') tree[rt].a[3][3] = 1, tree[rt].a[4][4] = 1;

        return ;
    }
    int m = l+r >> 1;
    build(ls);
    build(rs);
    push_up(rt);
}
Matrix query(int L, int R, int rt, int l, int r) {
    if(L <= l && r <= R) return tree[rt];
    int m = l+r >> 1;
    Matrix res;
    res.init();
    for (int i = 0; i < 5; ++i) res.a[i][i] = 0;
    if(L <= m) res = res * query(L, R, ls);
    if(R > m) res = res* query(L, R, rs);
    return res;
}
int main() {
    scanf("%d %d", &n, &q);
    scanf("%s", s+1);
    build(1, 1, n);
    while(q--) {
        scanf("%d %d", &l, &r);
        Matrix res = query(l, r, 1, 1, n);
        if(res.a[0][4] == INF) printf("-1\n");
        else printf("%d\n", res.a[0][4]);
    }
    return 0;
}

Codeforces 750 E New Year and Old Subsequence

标签：ons   cin   false   and   return   bug   print   back   fir   

原文地址：https://www.cnblogs.com/widsom/p/11512443.html