标签:pac imp util map test solution you new com
1. Two Sum
Easy
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
package leetcode; import java.util.HashMap; import java.util.Map; public class TwoSum { @org.junit.Test public void test() { int[] nums = { 2, 7, 11, 15 }; int target = 9; Solution solution = new Solution(); int[] result = solution.twoSum1(nums, target); System.out.println(result[0] + " " + result[1]); result = solution.twoSum2(nums, target); System.out.println(result[0] + " " + result[1]); result = solution.twoSum3(nums, target); System.out.println(result[0] + " " + result[1]); } } class Solution { public int[] twoSum1(int[] nums, int target) { for (int i = 0; i < nums.length; i++) { for (int j = i + 1; j < nums.length; j++) { if (nums[j] == target - nums[i]) { return new int[] { i, j }; } } } throw new IllegalArgumentException("No two sum solution"); } public int[] twoSum2(int[] nums, int target) { Map<Integer, Integer> map = new HashMap<>(); for (int i = 0; i < nums.length; i++) { map.put(nums[i], i); } for (int i = 0; i < nums.length; i++) { int complement = target - nums[i]; if (map.containsKey(complement) && map.get(complement) != i) { return new int[] { i, map.get(complement) }; } } throw new IllegalArgumentException("No two sum solution"); } public int[] twoSum3(int[] nums, int target) { Map<Integer, Integer> map = new HashMap<>(); for (int i = 0; i < nums.length; i++) { int complement = target - nums[i]; if (map.containsKey(complement)) { return new int[] { map.get(complement), i }; } map.put(nums[i], i); } throw new IllegalArgumentException("No two sum solution"); } }
标签:pac imp util map test solution you new com
原文地址:https://www.cnblogs.com/denggelin/p/11517583.html