For the spherically symmetric case, \(f\) is constant. Thus \[
\begin{equation}
D_as^a=\frac{1}{\sqrt{\gamma}}\partial_r (\sqrt{\gamma}s^r)
\end{equation}
\]
Because the spatial line element is written in a diagonal form,as \[
\begin{equation}
\gamma_{ij}=diag(\gamma_{rr},\gamma_{\theta\theta},\gamma_{\theta\theta}\sin{\theta}^2)
\end{equation}
\]
then \(D_as^a+K_{ab}s^as^b-K=0\) can be write as \[
\begin{equation}
\boxed{ \partial_r(log \gamma_{\theta\theta})-2\sqrt{\gamma_{rr}}K^\theta_\theta =0}
\end{equation}
\]
Indeed, \(A(r) =4\pi \gamma_{\theta\theta}(r)\) denotes the surface area of a radius, \(r\), and using the equation of \(\gamma_{\theta\theta}\) in the form \[ -2\alpha K^\theta_\theta=(\partial_t-\beta^r\partial_r)log \gamma_{\theta\theta}\]
the equation (3) is written as \[
\begin{equation}
( \partial_t+(\alpha \gamma^{-1/2}-\beta^r)\partial_r)A(r)=0, or, k^a\nabla_aA=0
\end{equation}
\] Thus, the apparent horizon in spherical symmetry may be defined as the surface where the local variation rate of its area along outgoing light rays is zero.