标签:style blog http color io os ar for sp
问题描述:
前缀表达式转成后缀表达式,示例:
* + 4 2 + 3 6 => 4 2 + 3 6 + *
思路(树):
1. 从左往右扫描串
2. 遇到操作符则递归构造树节点,当前操作符是根节点,并递归构造左右子节点
3. 后序遍历当前结果,并返回
代码:
1 #include <string> 2 #include <sstream> 3 #include <iostream> 4 5 using namespace std; 6 7 string input_str = "* + 4.3 2 + 3.5 6.2"; 8 int ind = 0; 9 10 //树结构 11 typedef struct BinaryTreeNode 12 { 13 string cur_str; 14 BinaryTreeNode *left; 15 BinaryTreeNode *right; 16 BinaryTreeNode(string _cur_str) 17 { 18 cur_str = _cur_str; 19 left = NULL; 20 right = NULL; 21 } 22 } BNode_t; 23 24 //后序遍历树 25 void post_traverse(BNode_t *root, string &post_str) 26 { 27 if( root == NULL ) 28 return; 29 post_traverse(root->left, post_str); 30 post_traverse(root->right, post_str); 31 if( post_str != "" ) 32 post_str += " " + root->cur_str; 33 else 34 post_str = root->cur_str; 35 } 36 37 //得到下一个 38 string get_next() 39 { 40 string next = ""; 41 for(; ind < input_str.size(); ind++) 42 { 43 if( input_str[ind] != ‘ ‘ ) 44 next += input_str[ind]; 45 else 46 break; 47 } 48 ind++; 49 return next; 50 } 51 52 //转换:递归构造树,并后序遍历 53 string transform() 54 { 55 string post_str; 56 string next = get_next(); 57 if( ! isdigit(next[0]) ) 58 { 59 BNode_t *root = new BNode_t(next); 60 root->left = new BNode_t( transform() ); 61 root->right = new BNode_t( transform() ); 62 post_traverse(root, post_str); 63 delete root->left; 64 delete root->right; 65 delete root; 66 return post_str; 67 } 68 else return next; 69 } 70 71 72 int main() 73 { 74 cout << transform() << endl; 75 return 0; 76 }
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http://www.cnblogs.com/breakthings/p/4053444.html
标签:style blog http color io os ar for sp
原文地址:http://www.cnblogs.com/breakthings/p/4053444.html