标签:output first bsp icp mina queue cas base str
Behind the scenes in the computer‘s memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution Mby N (for example, 8), you are supposed to point out the strictly dominant color.
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (≤) and N (≤) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.
For each test case, simply print the dominant color in a line.
5 3
0 0 255 16777215 24
24 24 0 0 24
24 0 24 24 24
24
题意:
数数哪个颜色过半
AC代码:
#include<iostream> #include<stack> #include<queue> #include<cmath> #include<algorithm> #include<vector> #include<string> #include<cstring> #include<algorithm> using namespace std; int a[99999999]; int main(){ int n,m; cin>>n>>m; int last=-1; for(int i=1;i<=m;i++){ for(int j=1;j<=n;j++){ int x; cin>>x; a[x]++; if(a[x]>n*m/2){ last=x; } } } cout<<last; return 0; }
PAT 甲级 1054 The Dominant Color (20 分)(简单题)
标签:output first bsp icp mina queue cas base str
原文地址:https://www.cnblogs.com/caiyishuai/p/11542676.html